Difference between revisions of "2016 AMC 8 Problems/Problem 13"
Reaganchoi (talk | contribs) |
|||
| Line 4: | Line 4: | ||
==Solution== | ==Solution== | ||
| − | {{ | + | The product is zero if and only if zero is one of the numbers that is chosen. 2 numbers are chosen out of 6 total, so the chance that the product is 0 is <math>\frac{2}{6}=\textbf{(D)} \frac{1}{3}</math>. |
| + | |||
{{AMC8 box|year=2016|num-b=12|num-a=14}} | {{AMC8 box|year=2016|num-b=12|num-a=14}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:54, 23 November 2016
13. Two different numbers are randomly selected from the set 
and multiplied together. What is the probability that the product is 
?
Solution
The product is zero if and only if zero is one of the numbers that is chosen. 2 numbers are chosen out of 6 total, so the chance that the product is 0 is 
.
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
