Difference between revisions of "2016 AMC 8 Problems/Problem 9"
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The prime factorization is <math>2016=2^5\times3^2\times7</math>. Since the problem is only asking us for the distinct prime factors, we have <math>2,3,7</math>. Their desired sum is then <math>\boxed{\textbf{(B) }12}</math>. | The prime factorization is <math>2016=2^5\times3^2\times7</math>. Since the problem is only asking us for the distinct prime factors, we have <math>2,3,7</math>. Their desired sum is then <math>\boxed{\textbf{(B) }12}</math>. | ||
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+ | {{AMC8 box|year=2016|num-b=8|num-a=10}} | ||
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Revision as of 09:46, 23 November 2016
What is the sum of the distinct prime integer divisors of ?
Solution
The prime factorization is . Since the problem is only asking us for the distinct prime factors, we have . Their desired sum is then .
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
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All AJHSME/AMC 8 Problems and Solutions |
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