Difference between revisions of "2019 AMC 12B Problems/Problem 12"
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==Problem== | ==Problem== | ||
+ | Right triangle <math>ACD</math> with right angle at <math>C</math> is constructed outward on the hypotenuse <math>AC</math> of isosceles right triangle <math>ABC</math> with leg length 1, as shown, so that the two triangles have equal perimeters. What is sin(2 BAD)? | ||
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+ | Would you please fix the Latex above? Thanks. | ||
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+ | <math>\textbf{(A) } \frac{1}{3} \qquad\textbf{(B) } \frac{\sqrt{2}}{2} \qquad\textbf{(C) } \frac{3}{4} \qquad\textbf{(D) } \frac{7}{9} \qquad\textbf{(E) } \frac{\sqrt{3}}{2}</math> | ||
==Solution== | ==Solution== |
Revision as of 16:39, 14 February 2019
Problem
Right triangle with right angle at is constructed outward on the hypotenuse of isosceles right triangle with leg length 1, as shown, so that the two triangles have equal perimeters. What is sin(2 BAD)?
Would you please fix the Latex above? Thanks.
Solution
D 7/9 (SuperWill)
See Also
2019 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 11 |
Followed by Problem 13 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |