Difference between revisions of "2020 AMC 10B Problems/Problem 1"
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− | ==Problem | + | ==Problem== |
− | |||
− | <math>\textbf{(A)}\ \qquad\textbf{(B)}\ \qquad\textbf{(C)}\ \qquad\textbf{(D)}\ \qquad\textbf{(E)}\ </math> | + | What is the value of |
+ | <cmath>1-(-2)-3-(-4)-5-(-6)?</cmath> | ||
+ | |||
+ | <math>\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21</math> | ||
+ | |||
+ | ==Solution== | ||
+ | We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>. | ||
+ | |||
+ | The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> ~quacker88 | ||
− | |||
− | |||
==Video Solution== | ==Video Solution== | ||
− | + | https://youtu.be/Gkm5rU5MlOU | |
− | == See Also == | + | |
+ | ~IceMatrix | ||
+ | |||
+ | |||
+ | https://youtu.be/-wciFhP5h3I | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==See Also== | ||
{{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}} | {{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 16:52, 16 June 2020
Contents
Problem
What is the value of
Solution
We know that when we subtract negative numbers, .
The equation becomes ~quacker88
Video Solution
~IceMatrix
~savannahsolver
See Also
2020 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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