Difference between revisions of "British Flag Theorem"

(New page: The '''British flag theorem''' says that if a point P is chosen inside rectangle ABCD then <math>AP^{2}+PC^{2}=BP^{2}+DP^{2}</math>. A---w--------B | | | z---P--------x...)
 
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Revision as of 20:34, 14 October 2007

The British flag theorem says that if a point P is chosen inside rectangle ABCD then $AP^{2}+PC^{2}=BP^{2}+DP^{2}$.

 A---w--------B
 |   |        |
 z---P--------x
 |   |        |
 |   |        |
 D---y--------C      
   Figure 1

The theorem also applies to points outside the square, although the proof is harder to visualize in this case.

Proof

In Figure 1, by the Pythagorean theorem, we have:

  • $AP^{2} = Aw^{2} + Az^{2}$
  • $PC^{2} = wB^{2} + zD^{2}$
  • $BP^{2} = wB^{2} + Az^{2}$
  • $PD^{2} = zD^{2} + Aw^{2}$

Therefore:

  • $AP^{2} + PC^{2} = Aw^{2} + Az^{2} + wB^{2} + zD^{2} = wB^{2} + Az^{2} + zD^{2} + Aw^{2} = BP^{2} + PD^{2}$

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