Difference between revisions of "De Moivre's Theorem"

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DeMoivre's Theorem is a very useful theorem in the mathematical fields of [[Complex numbers]]. It states that:
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'''DeMoivre's Theorem''' is a very useful theorem in the mathematical fields of [[complex numbers]]. It allows complex numbers in [[polar coordinates|polar]] form to be easily raised to certain powers. It states that for an <math>\left(\cos x+i\sin x\right)^n=\cos(nx)+i\sin(nx)</math>
 
 
<math>\left(\cos x+i\sin x\right)^n=\cos(nx)+i\sin(nx)</math>
 
 
 
  
 
== Proof ==
 
== Proof ==
This is one proof of DeMoivre's theorem by Mathematical Induction.
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This is one proof of De Moivre's theorem by [[induction]].
  
=== If <math>n>0</math> ===
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*If <math>n>0</math>, for <math>n=1</math>, the case is obviously true.
==== Part 1 ====
 
For <math>n=1</math>, the case is obviously true.
 
  
==== Part 2 ====
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:Assume true for the case <math>n=k</math>. Now, the case of <math>n=k+1</math>:
Assume true for the case <math>n=k</math>.
 
  
==== Part 3 ====
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:[[Image:DeMoivreInductionP1.gif]]
Now, the case of <math>n=k+1</math>.
 
  
[[Image:DeMoivreInductionP1.gif]]
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:Therefore, the result is true for all positive integers <math>n</math>.
  
Therefore, the result is true for all positive integers <math>n</math>.
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*If <math>n=0</math>, the formula holds true because <math>\cos(0x)+i\sin (0x)=1+i0=1</math>. Since <math>z^0=1</math>, the equation holds true.
  
=== If <math>n=0</math> ===
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*If <math>n<0</math>, one must consider <math>n=-m</math> when <math>m</math> is a positive integer.
The formula holds true when <math>n=0</math> because <math>\cos(0x)+i\sin (0x)=1+i0=1</math>. Since <math>z^0=1</math>, the equation holds true.
 
  
=== If <math>n<0</math> ===
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:[[Image:DeMoivreInductionP2.gif]]
If <math>n<0</math>, one must consider <math>n=-m</math> when <math>m</math> is a positive integer.
 
  
Therefore:
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And thus, the formula proves true for all integral values of <math>n</math>. <math>\Box</math>
  
[[Image:DeMoivreInductionP2.gif]]
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By [[Euler's formula]] (<math>e^{ix} = \cos x+i\sin x\right</math>), this can be extended to all real numbers <math>n</math>.
  
And thus, the formula proves true for all integral values of <math>n</math>. <math>\Box</math>
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[[Category:Theorems]]

Revision as of 20:10, 23 November 2007

DeMoivre's Theorem is a very useful theorem in the mathematical fields of complex numbers. It allows complex numbers in polar form to be easily raised to certain powers. It states that for an $\left(\cos x+i\sin x\right)^n=\cos(nx)+i\sin(nx)$

Proof

This is one proof of De Moivre's theorem by induction.

  • If $n>0$, for $n=1$, the case is obviously true.
Assume true for the case $n=k$. Now, the case of $n=k+1$:
DeMoivreInductionP1.gif
Therefore, the result is true for all positive integers $n$.
  • If $n=0$, the formula holds true because $\cos(0x)+i\sin (0x)=1+i0=1$. Since $z^0=1$, the equation holds true.
  • If $n<0$, one must consider $n=-m$ when $m$ is a positive integer.
DeMoivreInductionP2.gif

And thus, the formula proves true for all integral values of $n$. $\Box$

By Euler's formula ($e^{ix} = \cos x+i\sin x\right$ (Error compiling LaTeX. Unknown error_msg)), this can be extended to all real numbers $n$.