# Difference between revisions of "Fallacy"

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Then we have | Then we have | ||

− | + | <math> a^2 = ab </math> (since <math>a=b</math>) | |

− | + | ||

− | + | <math> 2a^2 - 2ab = a^2 - ab </math> (adding <math>a^2-2ab</math> to both sides) | |

− | + | ||

+ | <math> 2(a^2 - ab) = a^2 - ab </math> (factoring out a 2 on the [[LHS]]) | ||

+ | |||

+ | <math> 2 = 1 </math> (dividing by <math>a^2-ab</math>) | ||

[[Fallacious proof/2equals1 | Explanation]] | [[Fallacious proof/2equals1 | Explanation]] |

## Revision as of 14:39, 3 August 2006

A **fallacious proof** is a an attempted proof that is logically flawed in some way. The fact that a proof is fallacious says nothing about the validity of the original proposition.

## Common false proofs

The fallacious proofs are stated first and then links to the explanations of their fallacies follow.

### 2 = 1

Let .

Then we have

(since )

(adding to both sides)

(factoring out a 2 on the LHS)

(dividing by )

### All horses are the same color

We shall prove that all horses are the same color by induction on the number of horses.

First we shall show our base case, that all horses in a group of 1 horse have the same color, to be true. Of course, there's only 1 horse in the group so certainly our base case holds.

Now assume that all the horses in any group of horses are the same color. This is our inductive assumption.

Using our inductive assumption, we will now show that all horses in a group of horses have the same color. Number the horses 1 through . Horses 1 through must be the same color as must horses through . It follows that all of the horses are the same color.