Difference between revisions of "MIE 2015/Day 2/Problem 2"
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Latest revision as of 17:28, 11 January 2018
Problem 2
Let the functions , for , such that and , for every .
Compute .
Solution
First, let see the case
Now, when
Now, when
At this point it's easy to see the pattern. So, we just find the remainder of 2016 by 3.