User contributions
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- 16:11, 9 March 2011 (diff | hist) . . (+31) . . MATHCOUNTS (→Target Round)
- 13:34, 7 February 2011 (diff | hist) . . (+815) . . N 2003 AMC 12A Problems/Problem 14 (Created page with 'Since the area of square ABCD is 16, the side length must be 4. Thus, the side length of triangle AKB is 4, and the height of AKB, and thus DMC, is <math>2\sqrt{3}</math>. The …')
- 13:30, 7 February 2011 (diff | hist) . . (+238) . . 2003 AMC 12A Problems (→Problem 23)
- 13:25, 7 February 2011 (diff | hist) . . (+349) . . 2003 AMC 12A Problems (→Problem 20)
- 13:24, 7 February 2011 (diff | hist) . . (+656) . . 2003 AMC 12A Problems (→Problem 19)
- 13:21, 7 February 2011 (diff | hist) . . (+402) . . 2003 AMC 12A Problems (→Problem 16)
- 13:19, 7 February 2011 (diff | hist) . . (+717) . . 2003 AMC 12A Problems (→Problem 14)
- 21:00, 9 April 2009 (diff | hist) . . (+48) . . User:BOGTRO
- 23:50, 17 March 2009 (diff | hist) . . (+48) . . N User:Fantasylover (New page: This is Fantasylover. Fantasylover is a failure.)
- 23:49, 17 March 2009 (diff | hist) . . (+18) . . N User:BOGTRO (New page: My name is BOGTRO.)
- 17:56, 7 January 2009 (diff | hist) . . (+162) . . N 2000 AMC 10 Problems/Problem 15 (New page: <math>ab=a-b</math> <math>\frac{a}{b}+\frac{b}{a}-ab=\frac{a^2+b^2}{ab}-ab=\frac{-a^2b^2+a^2+b^2}{ab}</math> <math>\frac{-a^2+2ab-b^2+a^2+b^2}{ab}=2</math>. E.)
- 17:54, 7 January 2009 (diff | hist) . . (+616) . . N 2000 AMC 10 Problems/Problem 14 (New page: 71, 76, 80, 82, 91. The sum of the first 2 must be even, so we must choose 2 evens or the 2 odds. Let us look at the numbers (mod 3). 2,1,2,1,1. If we choose the two odds, the next num...)
- 17:49, 7 January 2009 (diff | hist) . . (+256) . . N 2000 AMC 10 Problems/Problem 13 (New page: The question is rather ambiguous, however I will assume that the pegs of the same color are distinguishable. Clearly, there is only 1 possible ordering if the colors are indistinguishable...)
- 17:47, 7 January 2009 (diff | hist) . . (+269) . . N 2000 AMC 10 Problems/Problem 12 (New page: We have a recursion: <math>A_n=A_{n-1}+4(n-1)</math>. I.E. we add increasing multiples of <math>4</math> each time we go up a figure. So, to go from Figure 0 to 100, we add <math>4 \cd...)
- 15:06, 7 January 2009 (diff | hist) . . (+426) . . N 2000 AMC 10 Problems/Problem 11 (New page: Two prime numbers between <math>4</math> and <math>18</math> are both odd. odd*odd=odd. odd-odd-odd=odd. Thus, we can discard the even choices. <math>ab-a-b=(a-1)(b-1)-1</math>. <mat...)
- 15:03, 7 January 2009 (diff | hist) . . (+197) . . N 2000 AMC 10 Problems/Problem 10 (New page: The largest possible value for <math>x</math> is <math>9</math>. The smallest is <math>3</math>. <math>9-3=6</math>. <math>8</math> is the smallest that cannot be made (of the choices li...)
- 15:03, 7 January 2009 (diff | hist) . . (+4) . . 2000 AMC 10 Problems/Problem 9
- 15:02, 7 January 2009 (diff | hist) . . (+105) . . N 2000 AMC 10 Problems/Problem 9 (New page: <math>|x-2|=p</math> <math>x<2</math>, so <math>2-x=p</math>. <math>x+p=2</math>. <math>x-p=2-2p</math>.)
- 15:02, 7 January 2009 (diff | hist) . . (+3) . . 2000 AMC 10 Problems/Problem 8
- 15:01, 7 January 2009 (diff | hist) . . (+188) . . N 2000 AMC 10 Problems/Problem 8 (New page: Let <math>f</math> be the number of freshman and s be the number of sophomores. <math>\frac{2}{5}f=\frac{4}{5}s</math>. <math>f=2s</math>. There are twice as many freshman as sophomores.)
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