Search results
Create the page "2011 AIME First Problem Problems/Problem 15" on this wiki! See also the search results found.
- == Problem 12 == ...<cmath> \frac mn = \frac{30\cdot 56 - 18\cdot 25}{30\cdot 56} = \frac{56 - 15}{56} = \frac{41}{56}.</cmath> Thus <math>m + n = 56 + 41 = \fbox{097}.</mat5 KB (848 words) - 19:15, 30 April 2023
- ==Problem 14== ...e of these triples are repeated and all are used. By the conditions of the problem, if <math>i</math> is the same in two different triples, then the two numbe10 KB (1,581 words) - 16:55, 27 May 2024
- == Problem 10 == Since <math>E</math> and <math>F</math> are midpoints, <math>BE = 15</math> and <math>CF = 7</math>.11 KB (1,720 words) - 03:12, 18 December 2023
- ==Problem== First, draw <math>O_1P,O_2P,BP,DP</math>. Then, observe that <math>\angle BAP=45<13 KB (2,055 words) - 05:25, 9 September 2022
- ==Problem== ...ber <math>x</math> is chosen at random from the interval <math>5 \le x \le 15</math>. The probability that <math>\lfloor\sqrt{P(x)}\rfloor = \sqrt{P(\lfl8 KB (1,273 words) - 14:03, 7 January 2023
- The '''Mock Geometry AIME 2011''' was created by AoPS user abacadaea. * [[Mock Geometry AIME 2011 Problems | Problems]]1 KB (136 words) - 11:29, 6 November 2016
- ==Problem 1== [[Mock Geometry AIME 2011 Problems/Problem 1|Solution]]8 KB (1,349 words) - 19:10, 14 June 2022
- ...alculating my projected score after guessing to see if I could qualify for AIME. My projected score was something around 122, so I got lucky.) '''AIME I:''' 4, never actually got the results back, so it's a guess.4 KB (701 words) - 19:50, 31 August 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. *[[2012 AIME I Problems]]1 KB (155 words) - 17:10, 15 March 2013
- {{AIME Problems|year=2012|n=I}} == Problem 1 ==10 KB (1,617 words) - 14:49, 2 June 2023
- The '''Mock AIME I 2011''' was created by AoPS users andersonw, [[User:Brut3Forc3|Brut3Forc3]], dys * [[Mock AIME I 2011 Problems | Problems]]1 KB (134 words) - 19:49, 28 January 2023
- ==Problem== Let <math>P(x) = x^{2013}+4x^{2012}+9x^{2011}+16x^{2010}+\cdots + 4052169x + 4056196 = \sum_{j=1}^{2014}j^2x^{2014-j}.</783 bytes (105 words) - 19:04, 15 December 2020
- [[1983 AIME Problems/Problem 1]] [[1983 AIME Problems/Problem 2]]24 KB (2,505 words) - 16:46, 19 March 2014
- ...o I have decided to go do some Oly prep :). Here's some oly notes/favorite problems. (There aren't that many examples, sorry.) B. Problem 1:80 KB (13,867 words) - 23:17, 22 December 2020
- == Problem 1 == [[2013 Mock AIME I Problems/Problem 1|Solution]]7 KB (1,149 words) - 17:16, 15 December 2020
- ...ike mathematics. Arcticturn has just started contributing to AMC problems, AIME, and is interested in helping others. He likes to doodle around on paper, t ...27 November 2021 (diff | hist) . . (-6) . . 2021 Fall AMC 10A Problems/Problem 24 (→Solution) (current)39 KB (3,190 words) - 20:10, 27 November 2021
- ...ther_solutions.2C_brief_use_of_rudimentary_limits.29 2019 AMC 10B Problems/Problem 18 Solution 5] (Combinatorics) ..._ANY_guess_and_check.2C_Chinese_Remainder_Theorem.29 2020 AMC 10A Problems/Problem 24 Solution 12] (Number Theory)7 KB (1,077 words) - 14:44, 8 February 2024
- c. 17,000-15,000 BC: The Lascaux cave paintings contain depictions of an omnipotent cat ...egend has it that, whichever company uncovers the books and publishes them first would monopolize the book-selling market, and is therefore Gmaas's Chosen O88 KB (14,928 words) - 13:54, 29 April 2024
- Proudest of: [[2019 AIME II Problems/Problem 15]] Solution 5 [[2023 USAJMO Problems/Problem 6]] Solution 110 KB (1,118 words) - 05:33, 13 January 2024
