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  • In the second iteration, i = 2, so Python prints 2. '''Find <math>\sum_{n=1}^{50} 2^{n}.</math>'''
    33 KB (5,277 words) - 22:14, 3 June 2023
  • ...the polygon. The number of interior angles in the polygon is <math>180(n-2)</math>. We know that the sum of all but one of them is <math>2190^{\circ} <cmath>180(n-2) > 2190</cmath>
    1 KB (184 words) - 14:00, 20 February 2020
  • ...ath>. By HL Congruency and CPCTC, <math>\angle AOC = \angle BOC = \theta /2</math>. <cmath>\cos (\theta /2) = \frac{3}{R}</cmath>
    2 KB (306 words) - 14:00, 20 February 2020
  • ...mber of games that a boy won is <math>\tfrac{7}{12} \cdot \tfrac{3n(3n-1)}{2} = \tfrac{7n(3n-1)}{8}.</math> ...is at least one boy playing is <math>\tfrac{3n(3n-1)}{2} - \tfrac{n(n-1)}{2}.</math> This means we can write and solve the following inequality.
    2 KB (328 words) - 15:50, 19 August 2018
  • ...cdots,</math> where the first term is 1, the next 2 terms are congruent to 2 modulo 3, the next 3 terms are congruent to 3 modulo 3, and so on.''' ...tion, the last number of each grouping is term number <math>\tfrac{n(n+1)}{2}.</math>
    1 KB (190 words) - 10:19, 22 August 2018
  • ...egative integer <math>n</math> we define <math>A_n = 2^{3n}+3^{6n+2}+5^{6n+2}</math>. Find the greatest common divisor of the numbers <math>A_0,A_1,\ldo Note that <math>A_0 = 2^0 + 3^2 + 5^2 = 35</math>, so the [[GCD]] must be a factor of 35. The prime factorizatio
    2 KB (226 words) - 13:30, 25 August 2018
  • ...the number <math>1</math>, then Todd must say the next two numbers (<math>2</math> and <math>3</math>), then Tucker must say the next three numbers (< 1 & 1 & 2-3 & 4-6 \\
    6 KB (1,052 words) - 17:48, 6 November 2021
  • ...6^2</math>, and applying difference of squares yields <math>(y-x)(y+x)=696^2</math>. Because <math>x</math> and <math>y</math> have the same parity (du Let <math>y+x = 2b</math> abd <math>y-x = 2a</math>; then <math>ab = 348^2</math>. Additionally,
    4 KB (674 words) - 16:03, 25 February 2021
  • ...ath>D</math> divides side <math>\overline{AC}</math> so that <math>AD:DC=1:2</math>. Let <math>E</math> be the midpoint of <math>\overline{BD}</math> an A = (1.2,1.7);
    27 KB (4,256 words) - 19:30, 17 January 2024
  • ==Solution 2== ...e. Now, in order to get <math>3</math> balls of each color, he needs <math>2</math> more of both <math>R</math> and <math>B</math>.
    11 KB (1,928 words) - 22:40, 12 November 2023
  • ...How many different ways are there to construct the <math>2 \times 2 \times 2</math> cube using these smaller cubes? (Two constructions are considered th ...cube. Each edge of the planar graph represents a shared face between <math>2</math> neighboring unit cubes. Each face of the planar graph represents a f
    10 KB (1,641 words) - 22:17, 26 September 2023
  • <math>\textbf{(A)} \, x^2 -x + 1 \qquad\textbf{(B)} \, x^2 + x + 1 \qquad\textbf{(C)} \, x^4 + 1 \qquad\textbf{(D)} \, x^6 - x^3 + 1 ...<math>1011</math> and <math>3033</math> are <math>3*337</math> and <math>3^2*337</math>, respectively.
    8 KB (1,325 words) - 02:14, 11 April 2024
  • ...egers is <math>2</math> greater than their median, and the median is <math>2</math> greater than their arithmetic mean. What is the least possible value ...> be the median. It follows that the two largest integers are both <math>M+2.</math>
    3 KB (517 words) - 13:07, 11 November 2023

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