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• User:Knm
  0 bytes (0 words) - 13:57, 6 August 2020

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• 2003 AMC 12A Problems/Problem 14
  ...ruent. Notice that <math>\angle{KNL}=45^\circ</math>, etc, so <math>\angle{KNM}=90^\circ</math>. So we have a square.
  3 KB (483 words) - 17:26, 22 June 2023
• 2019 AIME I Problems/Problem 6
  ...= \angle KMN = 90^{\circ}</math>. Thus, <math>\triangle KOP \sim \triangle KNM</math>.
  11 KB (1,717 words) - 20:11, 19 January 2024