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• Symmetry
  <cmath>\angle GPF = \angle GEQ \implies \triangle GFP \sim \triangle GQE \implies \frac {FP}{QE} = \frac {GP}{GE} \implies \frac
  19 KB (3,292 words) - 13:04, 13 May 2024
• 2001 JBMO Problems/Problem 3
  So we have <math>\angle GFP = \angle GAP = 30^{\circ}</math>, and <math>\angle PGF = \angle FAP = 30^{\ So <math>\angle GFP = \angle PGF</math>, implying that triangle <math>PGF</math> is an isoceles
  3 KB (565 words) - 00:59, 9 January 2023