Difference between revisions of "User:CreativeHedgehog/Templates/2 var linear equation"

 
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Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT)
 
Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT)
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It is not fully correct, and I am fixing its bugs. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 15:59, 8 August 2020 (EDT)
 
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Latest revision as of 15:59, 8 August 2020


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given a, b, c, d, e, and f, find x and y in the 2 equations below:

{{{a}}}x+{{{b}}}y={{{e}}}

{{{c}}}x+{{{d}}}y={{{f}}}

x=({{{e}}}*{{{d}}}-{{{b}}}*{{{f}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})

y=({{{a}}}*{{{f}}}-{{{e}}}*{{{c}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})



given a, b, c, d, e, and f, find x and y in the 2 equations below:

4x+2y=1

2x+4y=0

x=(1*4-2*0)/(4*4-2*2)

y=(4*0-1*2)/(4*4-2*2)


Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. CreativeHedgehog 14:42, 7 August 2020 (EDT)

It is not fully correct, and I am fixing its bugs. CreativeHedgehog 15:59, 8 August 2020 (EDT)