A Sort of Celebration Post
by mathnerd_101, Apr 11, 2025, 2:38 AM
So we've hit 10k, huh?
5 years ago, I set it as my dream to get to 10k views. I never thought I would get there. Who would want to look at some random teenager's blog? Who cares? This was the era where there were SO many AoPS users who were far smarter and better at writing than I was: mathicorn, v4913, bibear, sub_math, wolfpack, brianzjk, the list goes on. I did everything I could to get more views. Cringy little me even shamelessly advertised my blog on mathicorn's blog a few times
But here we are at my "goal." After meeting so many more new people, I guess I've built up a nonzero audience, which is pretty cool.
Now for a little history about my blog:
1. Where did your name come from?
Originally, every single post about this blog was about math. But as I realized 20000 other people were making posts on harder math problems with cooler solutions, I realized I wanted to deviate from this. Hence, "No Longer A Math Blog." I don't think I've deviated from the name since, as all of my posts have been on event recaps rather than math problems (Stay tuned for a little plot twist!)
2. Where did you get "Awaiting 2000 AoPS Upvotes" from?
Back in 8th grade, both simonicorn (who is unfortunately far past her AoPS days) and v4913 (who is also unfortunately past her AoPS days) both bet 2000 AoPS upvotes that I would make AIME. I didn't make AIME, and thus I am still awaiting the 1000 upvotes each that they owe me
Why did I keep this? Well, I was too lazy to change it but it also reminds me of my cringy, corny, oh-so "Don't ever show me the messages I sent then because I will otherwise want to rip my eyes out" days. And maybe that nostalgia is ok.
3. Where next?
I have no idea. Wherever this blog takes me, I guess. I know far too many people who have left AoPS and their blogs because they are "too old for AoPS." I currently don't believe that anybody is too old to make blog posts, but maybe my perspective will change when I enter college. We'll see. As for now, I have one goal: To provide high-qualitythough albeit long recaps of fun events that I have gone to.
And finally, the moment you all have waiting for: I'm breaking the rules that I had originally set for this blog: no math problems. Wake Tech Regionals was today, so I do want to go through a full solution set to all the problems I know how to solve. If you don't want to view it, great! It's in a hide tag for a reason. If you do want to view the problems, great! I invite you to click on the hide tag. Furthermore, I will do my best to give hints on how I approached the problem to aid you guys if you don't understand how to do the problem.
Problems and Solutions
And that's it. That's virtually all the problems minus one. This took like 2 hours to type up, so please do comment up watch it, and let me know if I made any mistakes. Shoutout to ChaitraliKA for both sharing me the problems and meeting up with me irl for the first time
Also shoutout to speedyfalcon for showing me how easy P5 actually was, and akliu for his work on helping me find solutions when I was being dumb.Also shoutout to theofficialpro orz on discord for helping your boy confirm his P10 solution.
5 years ago, I set it as my dream to get to 10k views. I never thought I would get there. Who would want to look at some random teenager's blog? Who cares? This was the era where there were SO many AoPS users who were far smarter and better at writing than I was: mathicorn, v4913, bibear, sub_math, wolfpack, brianzjk, the list goes on. I did everything I could to get more views. Cringy little me even shamelessly advertised my blog on mathicorn's blog a few times

But here we are at my "goal." After meeting so many more new people, I guess I've built up a nonzero audience, which is pretty cool.
Now for a little history about my blog:
1. Where did your name come from?
Originally, every single post about this blog was about math. But as I realized 20000 other people were making posts on harder math problems with cooler solutions, I realized I wanted to deviate from this. Hence, "No Longer A Math Blog." I don't think I've deviated from the name since, as all of my posts have been on event recaps rather than math problems (Stay tuned for a little plot twist!)
2. Where did you get "Awaiting 2000 AoPS Upvotes" from?
Back in 8th grade, both simonicorn (who is unfortunately far past her AoPS days) and v4913 (who is also unfortunately past her AoPS days) both bet 2000 AoPS upvotes that I would make AIME. I didn't make AIME, and thus I am still awaiting the 1000 upvotes each that they owe me

Why did I keep this? Well, I was too lazy to change it but it also reminds me of my cringy, corny, oh-so "Don't ever show me the messages I sent then because I will otherwise want to rip my eyes out" days. And maybe that nostalgia is ok.
3. Where next?
I have no idea. Wherever this blog takes me, I guess. I know far too many people who have left AoPS and their blogs because they are "too old for AoPS." I currently don't believe that anybody is too old to make blog posts, but maybe my perspective will change when I enter college. We'll see. As for now, I have one goal: To provide high-quality
And finally, the moment you all have waiting for: I'm breaking the rules that I had originally set for this blog: no math problems. Wake Tech Regionals was today, so I do want to go through a full solution set to all the problems I know how to solve. If you don't want to view it, great! It's in a hide tag for a reason. If you do want to view the problems, great! I invite you to click on the hide tag. Furthermore, I will do my best to give hints on how I approached the problem to aid you guys if you don't understand how to do the problem.
Problems and Solutions
Problem 1: Determine the area enclosed by the graphs of
Hint
Solution to P1
Problem 2: Calculate the sum of the real solutions to the equation
Hint
Solution to P2
Problem 3: List the two transformations needed to convert the graph
to 
Hint
Solution to P3
Problem 4: Let
be positive integers such that
and
Determine the value of 
Hint
Solution for P4
Problem 5: Eve and Oscar are playing a game where they roll a fair, six-sided die. If an even number occurs on two consecutive rolls, then Eve wins. If an odd number is immediately followed by an even number, Oscar wins. The die is rolled until one person wins. What is the probability that Oscar wins?
Hint
Solution to P5
Problem 6: In triangle
is on point
such that
and
and
is a point on
such that
and
Given that
calculate 
Hint
Solution to P6
Problem 7: Determine the sum of the zeroes of the quadratic of polynomial
given that 
Hint
Solution to Problem 7
Problem 8:
Hint
Solution to P8
Problem 9:
Find the sum of all real solutions to
Hint
Solution to P9
Problem 10:
Define the function
![\[f(x) =
\begin{cases}
x - 9, & \text{if } x > 100 \\
f(f(x + 10)), & \text{if } x \leq 100
\end{cases}\]](//latex.artofproblemsolving.com/4/e/5/4e5b4486030a59e74df648819a1a59f82622b3b7.png)
Calculate
.
Hint
Solution to P10
Problem 11:
Let
be real numbers such that
Find 
Hint
Solution to P11
Problem 12: Points
are on circle
such that
and
Determine the path length from
to
formed by segment
and arc 
Hint
Solution to P12
Problem 13: Determine the number of integers
such that the expression
is also an integer.
Hint
Solution to Problem 13
Problem 14: Determine the smallest positive integer
such that
is a multiple of 
Hint
Solution to Problem 14
Problem 15: Suppose
and
are real numbers such that
and
Calculate 
Funnily enough, I guessed this question right in contest.
Hint
Solution to Problem 15
Problem 16: A sequence of points
will follow the rules such that
How many sequences
are possible such that
is the only point with equal coordinates?
Hint
Solution to P16
Problem 17 (With a solution shamelessly stolen from akliu):
Calculate
Hint
Solution to P17
Problem 18: (Also stolen from akliu's blog post)
Calculate

Hint
Solution to Problem 18
Problem 19: Determine the constant term in the expansion of
Hint
Solution to P19
Problem 20 was a stupid "I'm either telling the truth vs I'm lying here's 5 statements figure out how many of the 5 statements are truth tellers" type of problems that I didn't have time to get to.
SHORT ANSWER QUESTIONS:
1. Five people randomly choose a positive integer less than or equal to
The probability that at least two people choose the same number can be written as
Find 
Hint
Solution to S1
2. Define a function
on the positive integers using the rule that for
For all prime
,
and for all other
Find the smallest possible value of
such that 
Hint
Solution to S2
3. How many integers
can be written as the sum of two distinct, non-negative integer powers of 
Huge shoutout to OTIS for teaching me how to solve problems like this.
Hint
Solution to S3
4. Let
be the set of positive integers of
such that
for some other positive integer
Find the only three-digit value of
in 
Hint
Solution to S4
5. Let
be a positive integer and let
be the integer that is formed by removing the first three digits from
Find the value of
with least value such that 
Hint
Solution to S5

The key to this problem is to just plug in some points in the LHS (I assume you guys already know how to graph the RHS). This lets you see what the graph is like, since sum of absolute values can be wonky sometimes.
Solution to P1
Funnily enough, I managed to silly P1 in-contest! Goes to show how well I did under a time crunch.

The solution to this is by graphing out both functions. Doing this gives us a pentagon, which we can find by complementary area. Note that we have a larger trapezoid and two smaller triangles. By finding the coordinates of the intersections, we get that our answer is

The solution to this is by graphing out both functions. Doing this gives us a pentagon, which we can find by complementary area. Note that we have a larger trapezoid and two smaller triangles. By finding the coordinates of the intersections, we get that our answer is

Problem 2: Calculate the sum of the real solutions to the equation

Hint
Do the substitution and then factor. Easy as that.
Solution to P2
The key to this is to substitute
Doing this, we get that
Now, we can solve this by factoring. By using RRT, we get that
is a factor. Upon division, we get
is the factored form. Now, we know that our only positive solutions are
so our values of
are
Summing these gives our answer of 
Remark: In contest, I started doing some crazy algebraic manipulation that was far too complicated. I overthought and wasted a lot of time. How lovely, given time was my biggest restraint.








Remark: In contest, I started doing some crazy algebraic manipulation that was far too complicated. I overthought and wasted a lot of time. How lovely, given time was my biggest restraint.
Problem 3: List the two transformations needed to convert the graph


Hint
I have no idea what to say here. Just... learn transformations...
Solution to P3
Wow so I got this VERY wrong. Looks like I need to brush up on 8th-grade math (as does virtually everyone else I know haha). Essentially you just plug in the answer choices and see where it gets you. The correct answer ends up being "Shift right by 3, Vertical dilation by a factor of 3" because you just substitute
in or something like that idk my friend explained it pretty wonkily idk if he even solved it right but anyhow we press on. Transformations suck.

Problem 4: Let




Hint
Remember your factorizations, kids. Also, it's helpful to always manipulate the desired expression first.
Solution for P4
By rewriting the denominator, we get that it is equal to
Furthermore, note that
Thus, the answer is just 



Problem 5: Eve and Oscar are playing a game where they roll a fair, six-sided die. If an even number occurs on two consecutive rolls, then Eve wins. If an odd number is immediately followed by an even number, Oscar wins. The die is rolled until one person wins. What is the probability that Oscar wins?
Hint
Don't overthink it like I did.
Solution to P5
If the first roll is odd, Oscar wins (Think about it. There is NO other way that there can be two evens before Oscar wins.) If the first roll is even, there's a 50% chance that the next roll is odd, and thus Oscar wins yet again. Thus, the probability is just 

Problem 6: In triangle











Hint
Similar triangles.
Solution to P6
By similar triangles, we get that
so
Cross multiplying and solving this quadratic, we get that our solution is
Thus, 




Problem 7: Determine the sum of the zeroes of the quadratic of polynomial


Hint
Substitute and boom system of equations
Solution to Problem 7
Denote
We know from
that
so substituting this gives us
Now, plugging this in to
and
gives us
Solving these equations gives us
Thus, by Vieta's, the sum of the roots is 









Problem 8:
Hint
Remember median properties, unlike my clown ahh
Solution to P8
I WANT TO BEGIN BY SAYING THAT I SPENT 5 MINS ON THIS PROBLEM, DIDN'T SOLVE IT AND JUST SOLVED IT IN <1 MINUTE.
Ok, anyhow.
Note that
thus by median properties (the 2:1 ratio split thingy), we know that
(For reference, I missed this part in-contest) Now, we can calculate
by the Pythagorean Theorem to be
and thus
Now, by Pythagorean theorem, we know that the altitude from
is
so our area is just 
Ok, anyhow.

Note that








Problem 9:
Find the sum of all real solutions to

Spam log properties
Solution to P9
Note that we can simplify this to
Thus, simplifying and substituting
we get that
Simple guess and check gives us
as our solutions. My dumb self forgot the former solution. Thus,
giving us
as our sum.






Problem 10:
Define the function
![\[f(x) =
\begin{cases}
x - 9, & \text{if } x > 100 \\
f(f(x + 10)), & \text{if } x \leq 100
\end{cases}\]](http://latex.artofproblemsolving.com/4/e/5/4e5b4486030a59e74df648819a1a59f82622b3b7.png)
Calculate

Hint
Try values of
that are close to 100

Solution to P10
Trying
we get that
Now if we try finding
we will realize that
this
pattern continues until we once again reach
thus
Now return to the problem statement;
but each inner function will just become
hence the answer is 










Problem 11:
Let



Hint
Abuse log properties
Solution to P11
By multiplying the first two equations, we get that
Thus, simplifying, we get that
or that
Plugging this in to the first equation, we get that
so this means that
Now,
thus 
Note: HOW DID I MISS THIS IN CONTEST WHAT WAS I THINKING... WAS I EVEN THINKING?!







Note: HOW DID I MISS THIS IN CONTEST WHAT WAS I THINKING... WAS I EVEN THINKING?!
Problem 12: Points









Hint
Draw a good diagram
Solution to P12
Yeah so basically we note that
is the diameter, thus we can draw
which is a right triangle with
and so by Special Right Triangles we do NOT in fact get
but rather 





Problem 13: Determine the number of integers


Hint
Substitute
.

Solution to Problem 13
Substituting
gives us that we need
to be an integer. Plugging in factors of
we see that there are
integers that work.




Problem 14: Determine the smallest positive integer



Hint
Legendre's
Solution to Problem 14
By Legendre's, we know that
Plugging in numbers gives us
as our smallest value.


Problem 15: Suppose





Funnily enough, I guessed this question right in contest.
Hint
Algebraic Manipulation on Sum of Cubes
Solution to Problem 15
Note that we can rewrite
Furthermore,
so
meaning that
. Thus,
and thus
giving us 







Problem 16: A sequence of points

![\[
p_1 = (0,0), \quad p_{i+1} = (x_i + 1, y_i) \text{ or } (x_i, y_i + 1), \quad p_{10} = (4,5).
\]](http://latex.artofproblemsolving.com/6/0/3/6036ef2619ffb1e91db0ab310388217e472490f2.png)


Hint
It's essentially a complementary counting problem
Solution to P16
By the scenario in Bertrand's ballot theorem, we know that our solution is just
Furthermore, we know that
so our answer is just 



Problem 17 (With a solution shamelessly stolen from akliu):
Calculate

Binomial Theorem
Solution to P17
The first thing here is to notice the
in the summation. Essentially, we have
. This is pretty recognizable if you get enough practice with choose functions. From here, notice that our sum is:
In other words, we want to find
. Consider the polynomial
. You might remember that the coefficient for
in such a polynomial is
. Since we only want the even terms, we can eliminate the odd terms by computing
, and then dividing by
. For a more simple demonstration, consider finding the even terms of
. We have
, and
. Adding, we removed the
term, and have double the sum of the coefficients of
and
, which both have even powers. This is also just a special case of Roots of Unity Filter, but that's completely unnecessary here. Now, just compute
and divide by
to get a total sum of
. Since we don't want the terms
and
in our sum, subtract by
and factor:
. Now, doesn't that
term look kind of weird? Well, we actually notice
, or
. Indeed, we can factor our summation value:
, and dividing by
, we have
is our answer! (Again, thank you akliu for both the problem statement and solution)




























Problem 18: (Also stolen from akliu's blog post)
Calculate

Hint
Consider the cycles between even and odd values of 

Solution to Problem 18
It's important to consider what plugging in
gives us. Notice that the term on the inside,
, just cycles in value every
terms. Drawing it out on the unit circle (which I heavily advise), it cycles between
and
. Now, consider what each term individually is: For certain
where
, we have
, or
. For
, we have
for when
is odd. Writing out these terms and caseworking on
, we can manually compute the sum. It's not that bad, it's just
terms! Anyways, the answer is
.















Problem 19: Determine the constant term in the expansion of

Hint
Binomial Theorem
Solution to P19
We know that it'll just be the term where it's
so our coefficient is just 


Problem 20 was a stupid "I'm either telling the truth vs I'm lying here's 5 statements figure out how many of the 5 statements are truth tellers" type of problems that I didn't have time to get to.
SHORT ANSWER QUESTIONS:
1. Five people randomly choose a positive integer less than or equal to



Hint
Complementary counting
Solution to S1
By complementary counting, we get that the probability is just
Thus, our answer is just 


2. Define a function









Hint
I honestly have no idea how to not bash this. Sorry.
Solution to S2
By bashing out every single value we get that 

3. How many integers


Huge shoutout to OTIS for teaching me how to solve problems like this.
Hint
Think of it in base
. We can have
etc.


Solution to S3
By noting that we can rewrite the set of values that satisfy the condition in base
we get that it is
Thus, we note that for an integer
the number of integers that are length
or below is
Since
we know that all values of
satisfy our conditions. Thus, our answer is just 








4. Let






Hint
Pell equations
Solution to S4
We wish to find a fundamental solution. By plugging and chugging, we get that
is our solution. For these Pell Equations, all solutions are of the form
for
Thus, we plug in
giving us
as our answer.





5. Let





Hint
I honestly have no idea what hint to give here... sorry.
Solution to S5
Let the number of digits of
be
and let
be our three-digit number that we remove. Thus, we can write
By our condition, we know that
or that
Furthermore, we know that
does not work, so we try
We know that
must have the last two digits
by the fact that it must be divisible by a
Noting that
doesn't work, we try
or that
This, miraculously, works, and thus our value of
is just 
















And that's it. That's virtually all the problems minus one. This took like 2 hours to type up, so please do comment up watch it, and let me know if I made any mistakes. Shoutout to ChaitraliKA for both sharing me the problems and meeting up with me irl for the first time

Also shoutout to speedyfalcon for showing me how easy P5 actually was, and akliu for his work on helping me find solutions when I was being dumb.Also shoutout to theofficialpro orz on discord for helping your boy confirm his P10 solution.
This post has been edited 9 times. Last edited by mathnerd_101, Apr 12, 2025, 2:34 AM