[/quote]
,
and 
.
.
of degree 
.![$[a;b]$](http://latex.artofproblemsolving.com/0/0/6/0066f4b2714f88cdaf883b00f877aa1355b7f9ef.png)
and Maxim will give in response the maximum value of 
![\[
v_p(n!) \leq \frac{n}{p - 1}
\]](http://latex.artofproblemsolving.com/5/7/c/57ca4d0a6532fb4b97687a97b9c1fb35ad02b9f2.png)
and 
Prove that
Let 
and 
Prove that
not isosceles, the incircle 
.
is the intersection of 
.
is the projection of 
onto 
.
cut 
.
is the projection of 
onto 
.
cut 
respectively. Prove 
are collinear
be the set of non-negative integers and 
be the set of positive real numbers. Let 
be a function such that 
and 
for all integers 
,
for all integers 
.
.
which satisfy 
![$ \frac{a+b+c}{3} \ge \sqrt[10]{\frac{a^3+b^3+c^3}{3}}$](http://latex.artofproblemsolving.com/c/d/a/cdae05ad34239366b0dd3921243522c711b6ae58.png)
method, I can assum 
![$ \frac{2x+\frac{1}{x^2}}{3} \ge \sqrt[10]{ \frac{2x^3+ \frac{1}{x^6}}{3}} $](http://latex.artofproblemsolving.com/c/d/4/cd481672bee1e87d8c97ac623436e0ec75cfa73a.png)
are given such that 
.
in natural numbers m and n.
denote the smallest possible value of 
where 
are sets such that 
and 
whenever 
.
and 
intersect at 
of the two circles touches 
at 
respectively. Let 
be the symmetric points of 
intersects circles 
respectively which are distinct from 
and 
are equal.
,
.
intersects 
at 
.
cuts segment 
at 
respectively. If 
and 
,
equals 
.
are points on a circle 
,
,
.
at 
is on 
such that 
.
intersects 
.
is the reflection of 
.
lies on the same circle.
Y by Adventure10, Mango247
Fill up each square of a 
by grid with an integer. Let 
be the configuration of 
squares obtained by taking a 
by grid and removing the central square. Given that for any such in the by grid, the sum of integers in its squares is positive, show there exist a 
by square such that the sum of its entries is also positive.
by grid with an integer. Let 
be the configuration of 
squares obtained by taking a 
by grid and removing the central square. Given that for any such in the by grid, the sum of integers in its squares is positive, show there exist a 
by square such that the sum of its entries is also positive.
,
and 
be 
and 
be the centres of the cells covered by 
be centres of the cells covered by 
Let 
be the position of 
and let 
be the corresponding sum. The sum 
is similarly defined. It is clear that, counting multiplicity, the cells covered by 
Thus
Since the LHS is positive, so is at least one of the term on the RHS.
