1953 AHSME Problems/Problem 34
Problem 34
If one side of a triangle is 
inches and the opposite angle is 
, then the diameter of the circumscribed circle is:
Solution
By the Extended Law of Sines, the diameter, or twice the circumradius 
, is given by
![\[2R=\frac{12\text{ inches}}{\sin30^\circ}=\boxed{\textbf{(C)}\ 24\text{ inches}}.\]](http://latex.artofproblemsolving.com/7/5/5/75596a154e9ec96281daf1cdaaa8996ed92d2181.png)
See Also
| 1953 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 33 |
Followed by Problem 35 | |
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