1955 AHSME Problems/Problem 14
Problem 14
The length of rectangle is % more than the side of square . The width of the rectangle is % less than the side of the square. The ratio of the areas, , is:
Solution
Let each of the square's sides be . The dimensions of the rectangle can be expressed as and . Therefore, the area of the rectangle is , while the square has an area of . The ratio of can be defined as , which ultimately leads to
See Also
1955 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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