1959 AHSME Problems/Problem 40
Contents
[hide]Problem
In , is a median. intersects at so that . Point is on . Then, if , equals:
Solution 1
Draw with on . We know that , since .
Likewise, since , we know that .
Thus, , which is answer .
Solution 2
Let and . By Menelaus' Theorem on and , we know the following:
See also
1959 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 39 |
Followed by Problem 41 | |
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