1968 AHSME Problems/Problem 16
Problem
If is such that and , then:
Solution
Because , when is positive. Because , when is negative. can never be , so these two inequalities cover all cases for the value of . Thus, our answer is .
See also
1968 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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