1976 AHSME Problems/Problem 4
Problem 4
Let a geometric progression with n terms have first term one, common ratio and sum , where and are not zero. The sum of the geometric progression formed by replacing each term of the original progression by its reciprocal is
Solution
The sum of a geometric series with terms, initial term , and ratio is . So, . Our initial sequence is , and replacing each terms with its reciprocal gives us the sequence . The sum is now .~MathJams
1976 AHSME (Problems • Answer Key • Resources) | ||
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