1976 AHSME Problems/Problem 6
Problem 6
If is a real number and the negative of one of the solutions of is a solution of , then the solutions of are
Solution
We let the roots of the first equation be and the roots of the second equation be . By Vieta's Formulas, and , and . So, . Thus, , , so , and .~MathJams
1976 AHSME (Problems • Answer Key • Resources) | ||
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