1978 AHSME Problems/Problem 6
Problem 6
The number of distinct pairs of real numbers satisfying both of the following equations:
is
Solution
If and , then we can break this into two cases.
Case 1:
If , then and
Therefore, or
This yields 2 solutions
Case 2:
If , this means that , and .
Because y can be negative or positive, this yields or
This yields another 2 solutions.
See Also
1978 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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