1979 AHSME Problems/Problem 9
Problem 9
The product of ![$\sqrt[3]{4}$](http://latex.artofproblemsolving.com/7/6/d/76d2673e0edcd66e327478de683eaf2867ef602d.png)
and ![$\sqrt[4]{8}$](http://latex.artofproblemsolving.com/c/2/4/c24745c800ec409802436f5bca5bf54c13d894c0.png)
equals
![$\textbf{(A) }\sqrt[7]{12}\qquad \textbf{(B) }2\sqrt[7]{12}\qquad \textbf{(C) }\sqrt[7]{32}\qquad \textbf{(D) }\sqrt[12]{32}\qquad \textbf{(E) }2\sqrt[12]{32}$](http://latex.artofproblemsolving.com/d/5/e/d5ee894ad5966c496ec16f45b42831232b423101.png)
Solution
Solution by e_power_pi_times_i
and can be expressed as 
and 
, so their product is ![$2^{\frac{17}{12}} = \boxed{\textbf{(E) } 2\sqrt[12]{32}}$](http://latex.artofproblemsolving.com/b/2/e/b2e52c269eaa208c7adf83298ab142dd64c38a5e.png)
.
See also
| 1979 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 8 |
Followed by Problem 10 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
