1981 AHSME Problems/Problem 28
Consider the set of all equations , where , , are real constants and for . Let be the largest positive real number which satisfies at least one of these equations. Then
Since and will be as big as possible, we need to be as big as possible, which means is as small as possible. Since is positive (according to the options), it makes sense for all of the coefficients to be .
Evaluating gives a negative number, 1, and a number greater than 1, so the answer is