1995 AHSME Problems/Problem 8
Problem
In , and . Points and are on and , respectively, and . If , then
Solution
is a right triangle with hypotenuse .
is similar to by angle-angle similarity since and , and thus .
Solving the above for , we get .
See also
1995 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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