1997 AJHSME Problems/Problem 11
Problem
Let mean the number of whole number divisors of . For example, because 3 has two divisors, 1 and 3. Find the value of
Solution
has factors, and has as factors, for a total of factors. Plugging and :
has factors of , so , and the answer is
See also
1997 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.