# 2001 AMC 8 Problems/Problem 10

## Problem

A collector offers to buy state quarters for 2000% of their face value. At that rate how much will Bryden get for his four state quarters?

$\text{(A)}\ 20\text{ dollars} \qquad \text{(B)}\ 50\text{ dollars} \qquad \text{(C)}\ 200\text{ dollars} \qquad \text{(D)}\ 500\text{ dollars} \qquad \text{(E)}\ 2000\text{ dollars}$

## Solution

$2000\%$ is equivalent to $20\times100\%$. Therefore, $2000\%$ of a number is the same as $20$ times that number. $4$ quarters is $1$ dollar, so Bryden will get $20\times1={20}$ dollars, $\boxed{\text{A}}$.

## Solution 2

Since $2000\%$ is just $\frac{2000}{100}$, we can multiply that by $100$, because four quarters is a $100$ cents. After the multiplication, we get $2000$. Since our answer is in cents right now, we need to convert it to dollars, which would be $\boxed{\text{(A) 20}}$ dollars.

## See Also

 2001 AMC 8 (Problems • Answer Key • Resources) Preceded byProblem 9 Followed byProblem 11 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.