2005 AMC 8 Problems/Problem 10
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[hide]Problem
Joe had walked half way from home to school when he realized he was late. He ran the rest of the way to school. He ran 3 times as fast as he walked. Joe took 6 minutes to walk half way to school. How many minutes did it take Joe to get from home to school?
Solution 1
We can use the equation where is the distance, is the rate, and is the time. The distances he ran and walked are equal, so , where is the rate at which he ran, is the time for which he ran, is the rate at which he walked, and is the time for which he walked. Because he runs three times faster than he walks, . We want to find the time he ran, minutes. He traveled for a total of minutes.
Solution 2
We know that it took Joe minutes to walk halfway. If he ran times as fast as that, he went minutes for the other half (as and if we multiply by we are essentially dividing by ). Therefore, we have minutes.
See Also
2005 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
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