2005 AMC 8 Problems/Problem 19
Problem
What is the perimeter of trapezoid ?
Solution
Draw altitudes from and to base to create a rectangle and two right triangles. The side opposite is equal to . The bases of the right triangles can be found using Pythagorean or special triangles to be and . Add it together to get . The perimeter is .
Video Solution
https://youtu.be/h0V8qcEo0U8 Soo, DRMS, NM
Video Solution by OmegaLearn
https://youtu.be/abSgjn4Qs34?t=2362
~ pi_is_3.14
See Also
2005 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.