2005 CEMC Gauss (Grade 7) Problems/Problem 14
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[hide]Problem
The numbers on opposite sides of a die total . What is the sum of the numbers on the unseen faces of the two dice shown?
Solution 1
Since the sum of the numbers on opposite faces on a die is , then and are on opposite faces, and are on opposite faces, and and are on opposite faces. On the first die, the numbers on the unseen faces opposite the , , and are , , and respectively. On the second die, the numbers on the unseen faces opposite the , , and are , , and respectively. The sum of the missing numbers is . Therefore, the answer is .
Solution 2
The sum of the numbers on a die is and so the sum of the numbers on two die is . Since there is a sum of showing on the six visible faces, the sum of the numbers on the six unseen faces is . The correct answer is .
See Also
2005 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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CEMC Gauss (Grade 7) |