2010 AMC 12B Problems/Problem 12
Contents
[hide]Problem
For what value of does
Solution 1
Solution 2
Using the fact that , we see that the equation becomes . Thus, and , so , or .
See also
2010 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 11 |
Followed by Problem 13 |
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All AMC 12 Problems and Solutions |
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