2012 AMC 10A Problems/Problem 4
Problem
Let and . What is the smallest possible degree measure for ?
Solution
and share ray . In order to minimize the value of , should be located between and .
, so . The answer is
Video Solution (CREATIVE THINKING)
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See Also
2012 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AMC 10 Problems and Solutions |
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