2020 AIME II Problems/Problem 4
Triangles and lie in the coordinate plane with vertices , , , , , . A rotation of degrees clockwise around the point where , will transform to . Find .
After sketching, it is clear a rotation is done about . Looking between and , and . Solving gives . Thus . ~mn28407
Solution 2 (Official MAA)
Because the rotation sends the vertical segment to the horizontal segment , the angle of rotation is degrees clockwise. For any point not at the origin, the line segments from to and from to are perpendicular and are the same length. Thus a clockwise rotation around the point sends the point to the point . This has the solution . The requested sum is .
We first draw a diagram with the correct Cartesian coordinates and a center of rotation . Note that because lies on the perpendicular bisector of (it must be equidistant from and by properties of a rotation).
Since is vertical while is horizontal, we have that the angle of rotation must be , and therefore . Therefore, is a 45-45-90 right triangle, and .
We calculate to be . Since we translate right and up to get from point to point , we must translate right and down to get to point . This gives us . Our answer is then . ~Lopkiloinm & samrocksnature
For the above reasons, the transformation is simply a rotation. Proceed with complex numbers on the points and . Let be the origin. Thus, and . The transformation from to is a multiplication of , which yields . Equating the real and complex terms results in the equations and . Solving,
We know that the rotation point has to be equidistant from both and so it has to lie on the line that is on the midpoint of the segment and also the line has to be perpendicular to . Solving, we get the line is . Doing the same for and , we get that . Since the point of rotation must lie on both of these lines, we set them equal, solve and get: ,. We can also easily see that the degree of rotation is since is initially vertical, and now it is horizontal. Also, we can just sketch this on a coordinate plane and easily realize the same. Hence, the answer is
~North America Math Contest Go Go Go
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