2021 AMC 12B Problems/Problem 16
Let be a polynomial with leading coefficient whose three roots are the reciprocals of the three roots of where What is in terms of and
Note that has the same roots as , if it is multiplied by some monomial so that the leading term is they will be equal. We have so we can see that Therefore
Solution 2 (Vieta's bash)
Let the three roots of be , , and . (Here e does NOT mean 2.7182818...) We know that , , and , and that (Vieta's). This is equal to , which equals . -dstanz5
Solution 3 (Fakesolve)
Because the problem doesn't specify what the coefficients of the polynomial actually are, we can just plug in any arbitrary polynomial that satisfies the constraints. Let's take . Then has a triple root of . Then has a triple root of , and it's monic, so . We can see that this is , which is answer choice .
If we let and be the roots of , and . The requested value, , is then The numerator is (using the product form of ) and the denominator is , so the answer is
Solution 5 (Good at Guessing)
The function . If it's , then it becomes So, becomes , so becomes . Also, there is a so the answer must include . The only answer having both of these is .
-Extremelysupercooldude (Minor Latex Edits and Grammar)
It is well known that reversing the order of the coefficients of a polynomial turns each root into its corresponding reciprocal. Thus, a polynomial with the desired roots may be written as . As the problem statement asks for a monic polynomial, our answer is
Video Solution by OmegaLearn
Video Solution by Punxsutawney Phil
Video Solution by OmegaLearn (Vieta's Formula)
Video Solution by Hawk Math
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