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- ...combinatorics, and number theory, along with sets of accompanying practice problems at the end of every section. ...88606&sprefix=after+school+maths+%2Caps%2C268&sr=8-2 100 Challenging Maths Problems]23 KB (3,038 words) - 18:33, 15 February 2025
- These '''Logic books''' are recommended by [[Art of Problem Solving]] administrators and m === Digital Logic===1 KB (151 words) - 13:14, 19 December 2008
- '''Mathematics''' is the study of structures which come from [[logic]]. Mathematics is important to the many [[science]]s because it provides ri ...ntity given a name and usually denoted by a letter or symbol. Many contest problems test one's fluency with [[algebraic manipulation]].6 KB (846 words) - 19:30, 13 February 2025
- ...ltiple Choice|difficulty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}} The AMC 8 exam is a 25 problem exam. There are 40 minutes given in the exam. Problems increase in difficulty as the problem number increases. Students are not pe4 KB (584 words) - 23:33, 15 January 2025
- ...math>|A\cap B|</math>, that's just putting four guys in order. By the same logic as above, this is <math>2!\binom{6}{4}=30</math>. Again, <math>|A\cap C|</m [[2011 AMC 8 Problems/Problem 6]]9 KB (1,703 words) - 00:20, 7 December 2024
- The exact same logic applies to the third digit; it can be any of the <math>8</math> digits exce ''[[2001 AMC 12 Problems/Problem 16 | 2001 AMC 12 Problem 16]]: A spider has one sock and one shoe f13 KB (2,018 words) - 14:31, 10 January 2025
- ...emonstrate casework in action. Unlike the selections in this article, most problems cannot be completely solved through casework. However, it is crucial as an While there are problems where casework produces the most elegant solution, in those where a shorter5 KB (709 words) - 16:40, 24 September 2024
- ...don't want, then subtracts that from the total number of possibilities. In problems that involve complex or tedious [[casework]], complementary counting is oft ''[[2006 AMC 10A Problems/Problem 21 | 2006 AMC 10A Problem 21]]: How many four-digit positive intege8 KB (1,192 words) - 16:20, 16 June 2023
- ...e with 5 possible answer choices. The remaining levels have tests with 30 problems, each multiple choice with 5 possible answer choices. ...thin the second one-third of the test is worth 4 points, and the remaining problems are worth 5 points. No penalty or partial credit is given to unanswered or6 KB (933 words) - 14:34, 17 February 2025
- .... It encompasses a variety of subjects such as geometry, algebra, and even logic. ...s math competition is similar to MOEMS (easier problems) and AMC 8 (harder problems)1 KB (164 words) - 20:19, 18 February 2025
- We now see a pattern! Using the exact same logic, we can condense this whole messy thing into a closed form: [[Category:Intermediate Number Theory Problems]]10 KB (1,702 words) - 21:23, 25 July 2024
- By logic <math>s=3</math> and <math>sr=5 \implies r=5/3.</math> [[Category:Introductory Geometry Problems]]6 KB (958 words) - 22:29, 28 September 2023
- ==Problems== ([[2005 AMC 12A Problems/Problem 13|Source]])11 KB (2,019 words) - 16:20, 7 July 2024
- ...h> but not <math>d</math> and thus would not be a perfect square, the same logic would apply if <math>d</math> was bigger than <math>b</math>, thus <math>b= [[Category:Intermediate Number Theory Problems]]2 KB (451 words) - 19:19, 20 December 2024
- ...{4} = 10(p-10)</math>. This equation is the same as above, and by the same logic, the answer is <math>n=\boxed{25}</math>. * [[AIME Problems and Solutions]]5 KB (772 words) - 21:14, 18 June 2020
- ~Azjps (Fundamental Logic) Here is a similar problem from another AIME test: [[2003 AIME II Problems/Problem 13|2003 AIME II Problem 13]], in which we have an equilateral trian19 KB (3,128 words) - 20:38, 23 July 2024
- ...additional T's among the first <math>4</math> spaces. We can use identical logic to show why we can divide the two H's among the last four spaces to get exa * [[AIME Problems and Solutions]]4 KB (772 words) - 20:09, 7 May 2024
- ...AD + BD' = 425 - DD'</math>. Thus <math>DD' = 425 - d</math>. By the same logic, <math>EE' = 450 - d</math>. [[Category:Intermediate Geometry Problems]]11 KB (1,879 words) - 20:04, 8 December 2024
- ...h term is <math>729</math> plus the <math>36</math>th term. Using the same logic, the <math>36</math>th term is <math>243</math> plus the <math>4</math>th t * [[AIME Problems and Solutions]]5 KB (866 words) - 23:00, 21 December 2022
- ...x^2-x-1)</math> into <math>1</math>. We can similarly continue to use this logic, by repeatedly cancelling out the middle term, and obtain the process: [[Category:Intermediate Algebra Problems]]10 KB (1,595 words) - 15:30, 24 August 2024