Search results

Page title matches

  • ...ence <math>\{a_{0},a_{1},a_{2},\ldots\}</math> is said to obey a '''linear recurrence of order <math>k</math>''' if there exist constants <math>c_{0},c_{1},\ldot
    315 bytes (56 words) - 22:32, 2 June 2011

Page text matches

  • Next, we set up a recurrence. Let <math>a_n</math> be the number of ways <math>n</math> indistinguishabl ...down however, there will only be one way to arrange the coins. We can the recurrence: <cmath>a_n=a_{n-1}+1.</cmath> Note <math>a_1=2</math>, so <math>a_8 = 9</m
    5 KB (830 words) - 00:51, 1 March 2023
  • After this, we can simply use the recurrence relation for <math>S_n</math>, finding
    9 KB (1,491 words) - 00:23, 26 December 2022
  • ...his is more easily visually demonstrated than proven.) We can repeat this recurrence, adding one every time we pair an odd to an even (but ignoring the pairing
    6 KB (899 words) - 19:58, 12 May 2022
  • ...>th crawl (as it will be forced to move somewhere else.). Thus, we get the recurrence relation <cmath>a_n=3^{n-1}-a_{n-1}.</cmath> ...he probability that the bug is on some other vertex. We have the following recurrence relations. <cmath>A_n = \frac{1}{3}O_{n-1}</cmath> <cmath>O_n = A_{n-1} + \
    19 KB (3,128 words) - 20:38, 23 July 2024
  • A [[linear recurrence | recurrence]] of the form <math>T_n=AT_{n-1}+BT_{n-2}</math> will have the closed form Suppose we have such a recurrence with <math>T_1=3</math> and <math>T_2=7</math>. Then <math>T_3=ax^3+by^3=16
    4 KB (644 words) - 15:24, 28 May 2023
  • By multiplying both sides of the previous recurrence relation and taking the sum of the terms <math>\forall n\geq 1</math>, we g We can perform a similar analysis on <math>c_{1,n}</math> to get the recurrence relation
    5 KB (923 words) - 12:17, 16 September 2024
  • ...owever, things start to look messy, and it looks like we have to break our recurrence down into even smaller cases, which is something that we don't like -- we w We thus have established a recurrence relation -- since the first house either gets mail or it doesn't, and canno
    15 KB (2,728 words) - 14:36, 23 December 2024
  • ...f(1) = 3</math> (A, B or C) and the answer is just <math>f(7)</math>. The recurrence relation can be found by considering the last letter of one of the valid st
    2 KB (336 words) - 16:29, 30 July 2022
  • ...math>. (<math>P</math> is called the ''characteristic polynomial'' of this recurrence.) ...ath>, <math>d_n=\beta^n</math> and <math>d_n=\gamma^n</math> satisfies the recurrence. Moreover, we know the following facts:
    3 KB (568 words) - 14:50, 3 April 2012
  • From the recurrence <math>!n=n\cdot!(n-1)+(-1)^{n}</math>, we can find that <math>\lim_{n\to\in
    3 KB (473 words) - 11:57, 20 February 2024
  • A sequence <math>\{R_n\}_{n \ge 0}</math> obeys the recurrence <math>7R_n = 64 - 2R_{n-1} + 9R_{n-2}</math> for any integers <math>n \ge 2
    6 KB (1,100 words) - 21:35, 9 January 2016
  • ...th>n\ge 1</math>. To do this, we use the following matrix form of a linear recurrence relation ...math>n\ge 1</math>. We conclude that <math>a_n</math> satisfies the linear recurrence <math>a_{n+1}=225a_n-a_{n-1}</math>.
    13 KB (2,214 words) - 16:39, 28 November 2024
  • ...F_{n-1} + F_{n-2}.</math> This is a constant coefficient linear homogenous recurrence relation. We also know that <math>F_0 = 0</math> and <math>F_1 = 1.</math>
    6 KB (953 words) - 20:37, 30 May 2024
  • ...so far are rational, even though there is an abundance of radicals in the recurrence. This motivates us to look at our discriminants in the quadratic formula th Plugging this into our recurrence formula gives us
    9 KB (1,482 words) - 12:52, 4 April 2024
  • This gives us the recurrence <math>T_n = T_{n-1} + T_{n-3}</math> for <math>n\geq 3</math>.
    2 KB (289 words) - 07:40, 26 January 2009
  • ...rential equations]] (ordinary or partial), [[difference equations]], and [[recurrence relations]]. Almost every technical field requires the consideration of dyn
    789 bytes (107 words) - 20:52, 18 October 2017
  • ==Solution 3 (plain recurrence solving) == ...t guessing the form of the solution at this point we can easily solve this recurrence. Note that one can easily get rid of the "<math>+2</math>" as follows: Let
    5 KB (682 words) - 08:45, 18 February 2022
  • Using this recurrence, we compute:
    3 KB (470 words) - 00:12, 28 January 2009
  • We can solve this problem by finding a particular solution for each linear recurrence.
    3 KB (555 words) - 10:38, 3 June 2024
  • Note that the recurrence <math>a_n+a_{n+1}-a_{n+2}~=~a_{n+3}</math> can be rewritten as <math>a_n+a_ ...2-r-1 = 1</math>, so <math>(r-1)(r+1)^2 = 1</math>, so our formula for the recurrence is <math>a_n = A + (B + Cn)(-1)^n</math>.
    3 KB (509 words) - 11:03, 15 December 2024

View (previous 20 | next 20) (20 | 50 | 100 | 250 | 500)