# Stewart's theorem

## Contents

## Statement

Given a triangle with sides of length opposite vertices are , , , respectively. If cevian is drawn so that , and , we have that . (This is also often written , a form which invites mnemonic memorization, i.e. "A man and his dad put a bomb in the sink.")

## Proof 1

Applying the Law of Cosines in triangle at angle and in triangle at angle , we get the equations

Because angles and are supplementary, . We can therefore solve both equations for the cosine term. Using the trigonometric identity gives us

Setting the two left-hand sides equal and clearing denominators, we arrive at the equation: . However, so and This simplifies our equation to yield or Stewart's theorem.

## Proof 2 (Pythagorean Theorem)

Let the altitude from to meet at . Let , , and . So, applying Pythagorean Theorem on yields

Since ,

Applying Pythagorean on yields

Substituting , , and in and gives

Notice that

are equal to each other. Thus, Rearranging the equation gives Stewart's Theorem:

~sml1809

## Nearly Identical Video Proof with an Example by TheBeautyofMath

~IceMatrix