Talk:Geometric inequality

Shouldn't the sign for the Isoperimetric Inequality be $\le$ not $<$ since a circle is a figure and $\frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1$?

--Xantos C. Guin 19:26, 24 June 2006 (EDT)

That's what I think, too. Fixed.

--CLee