Difference between revisions of "2020 AMC 8 Problems/Problem 1"
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==Solution 1== | ==Solution 1== | ||
| − | Luka will need <math>3\cdot 2=6</math> cups of sugar, and thus <math>6\cdot 4=24</math> cups of water. The answer is <math>\boxed{\textbf{(E) } | + | Luka will need <math>3\cdot 2=6</math> cups of sugar, and thus <math>6\cdot 4=24</math> cups of water. The answer is <math>\boxed{\textbf{(E) } 4}</math>. |
==Solution 2== | ==Solution 2== | ||
Revision as of 12:50, 23 November 2020
Problem
Luka is making lemonade to sell at a school fundraiser. His recipe requires 
times as much water as sugar and twice as much sugar as lemon juice. He uses 
cups of lemon juice. How many cups of water does he need?
Solution 1
Luka will need 
cups of sugar, and thus 
cups of water. The answer is 
.
Solution 2
We have that 
, so Luka needs 
cups.
Video Solution
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
