Difference between revisions of "2021 AMC 12B Problems/Problem 10"
MRENTHUSIASM (talk | contribs) m (→Solution: Rewrote the <= to \leq) |
|||
Line 13: | Line 13: | ||
<math>(x+1)(y+1)=704</math> | <math>(x+1)(y+1)=704</math> | ||
− | Looking at the possible divisors of <math>704 = 2^6*11</math>, <math>22</math> and <math>32</math> are within the constraints of <math>0 < x | + | Looking at the possible divisors of <math>704 = 2^6*11</math>, <math>22</math> and <math>32</math> are within the constraints of <math>0 < x \leq y \leq 37</math> so we try those: |
<math>(x+1)(y+1) = 22 * 32</math> | <math>(x+1)(y+1) = 22 * 32</math> |
Revision as of 17:45, 18 February 2021
Contents
[hide]Problem
Two distinct numbers are selected from the set so that the sum of the remaining numbers is the product of these two numbers. What is the difference of these two numbers?
Solution
The sum of the first integers is given by , so .
Therefore,
Rearranging,
Looking at the possible divisors of , and are within the constraints of so we try those:
Therefore, the difference , choice E). ~ SoySoy4444
Video Solution by Punxsutawney Phil
https://YouTube.com/watch?v=yxt8-rUUosI&t=292s
Video Solution by OmegaLearn (Simon's Favorite Factoring Trick)
~ pi_is_3.14
Video Solution by Hawk Math
https://www.youtube.com/watch?v=p4iCAZRUESs
See Also
2021 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 9 |
Followed by Problem 11 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.