Difference between revisions of "2021 Fall AMC 10A Problems/Problem 6"
MRENTHUSIASM (talk | contribs) (Created page with "== Problem == Elmer the emu takes <math>44</math> equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in <...") |
MRENTHUSIASM (talk | contribs) m |
||
Line 10: | Line 10: | ||
~MRENTHUSIASM | ~MRENTHUSIASM | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC10 box|year=2021 Fall|ab=A|num-b=5|num-a=7}} | ||
+ | {{MAA Notice}} |
Revision as of 20:06, 22 November 2021
Problem
Elmer the emu takes equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in equal leaps. The telephone poles are evenly spaced, and the st pole along this road is exactly one mile ( feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?
Solution
There are gaps between the telephone poles, so the distance of each gap is feet.
Each of Oscar's leap covers feet, and each of Elmer's strides covers feet. Therefore, Oscar's leap is feet longer than Elmer's stride.
~MRENTHUSIASM
See Also
2021 Fall AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.