Difference between revisions of "2023 AMC 8 Problems/Problem 2"
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==Solution 1 (Vague)== | ==Solution 1 (Vague)== | ||
− | Notice how the paper is folded. The bottom right corner of the twice-folded paper has to be the middle of the unfolded paper. So if you cut it in the way that it is shown in the problem, you find (it has to be symmetrical) that the cuts make an equilateral rhombus [tilted square] centered in the middle of the paper. | + | Notice how the paper is folded. The bottom right corner of the twice-folded paper has to be the middle of the unfolded paper. So if you cut it in the way that it is shown in the problem, you find (it has to be symmetrical) that the cuts make an equilateral rhombus [tilted square] centered in the middle of the paper, so the answer is (E). |
-claregu | -claregu |
Revision as of 00:51, 26 January 2023
Contents
[hide]Problem
A square piece of paper is folded twice into four equal quarters, as shown below, then cut along the dashed line. When unfolded, the paper will match which of the following figures?
Solution 1 (Vague)
Notice how the paper is folded. The bottom right corner of the twice-folded paper has to be the middle of the unfolded paper. So if you cut it in the way that it is shown in the problem, you find (it has to be symmetrical) that the cuts make an equilateral rhombus [tilted square] centered in the middle of the paper, so the answer is (E).
-claregu
Solution 2 (Thorough)
Notice that when we unfold the paper from the vertical fold line, we get
Then, if we unfold the paper from the horizontal fold line, we result in
It is clear that the answer is
~MrThinker
Video Solution by Magic Square
https://youtu.be/-N46BeEKaCQ?t=5658
See Also
2023 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.