Difference between revisions of "2003 AMC 8 Problems/Problem 20"
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==Video Solution== | ==Video Solution== | ||
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+ | ~David | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2003|num-b=19|num-a=21}} | {{AMC8 box|year=2003|num-b=19|num-a=21}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 18:57, 15 April 2023
Contents
[hide]Problem
What is the measure of the acute angle formed by the hands of the clock at 4:20 PM?
Solution 1
Imagine the clock as a circle. The minute hand will be at the 4 at 20 minutes past the hour. The central angle formed between and is degrees (since it is 1/12 of a full circle, 360). By , the hour hand would have moved way from 4 to 5 since is reducible to . One third of the way from 4 to 5 is one third of 30 degrees, which is 10 degrees past the 4. Recall that the minute hand is at the 4, so the angle between them is , and we are done.
Solution 2
You may also use the formula to yield a result in only ~10 seconds
-sub_math
Video Solution
https://www.youtube.com/watch?v=6FdbHSooYSA
~David
See Also
2003 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.