Difference between revisions of "1968 AHSME Problems/Problem 27"

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== See also ==
 
== See also ==
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[[Category: Intermediate Algebra Problems]]
 
[[Category: Intermediate Algebra Problems]]
 
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{{MAA Notice}}

Latest revision as of 00:53, 16 August 2023

Problem

Let $S_n=1-2+3-4+\cdots +(-1)^{n-1}n$, where $n=1,2,\cdots$. Then $S_{17}+S_{33}+S_{50}$ equals:

$\text{(A) } 0\quad \text{(B) } 1\quad \text{(C) } 2\quad \text{(D) } -1\quad \text{(E) } -2$

Solution

If $n$ is even, $S_{n}$ is negative $n/2$. If $n$ is odd, then $S_{n}$ is $(n+1)/2$. (These can be found using simple calculations.) Therefore, we know $S_{17}+S_{33}+S_{50}$ =$9+17-25$, which is $\fbox{B}$.


Solution By FrostFox

See also

1968 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 26
Followed by
Problem 28
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

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