Difference between revisions of "2010 AMC 8 Problems/Problem 6"
MRENTHUSIASM (talk | contribs) m (Undo revision 160328 by Raina0708 (talk) I PM'ed Raina0708 for suggesting NOT to erase LaTeX. So, I will restore the LaTeX code. LaTeX makes solutions more professional.) (Tag: Undo) |
(→See Also) |
||
(4 intermediate revisions by the same user not shown) | |||
Line 21: | Line 21: | ||
Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>. | Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>. | ||
+ | |||
+ | |||
+ | |||
+ | ==Video Solution by @MathTalks== | ||
+ | https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT | ||
+ | |||
+ | |||
+ | |||
+ | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2010|num-b=5|num-a=7}} | {{AMC8 box|year=2010|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 18:16, 15 October 2023
Problem
Which of the following figures has the greatest number of lines of symmetry?
Solution
An equilateral triangle has lines of symmetry.
A non-square rhombus has
lines of symmetry.
A non-square rectangle has
lines of symmetry.
An isosceles trapezoid has
line of symmetry.
A square has
lines of symmetry.
Therefore, the answer is .
Video Solution by @MathTalks
https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.