Difference between revisions of "1959 AHSME Problems/Problem 3"
Treetor10145 (talk | contribs) (Added Problem, Solution, and See Also) |
m (added link) |
||
(One intermediate revision by the same user not shown) | |||
Line 4: | Line 4: | ||
==Solution== | ==Solution== | ||
− | Note that a kite has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is <math>\boxed{\textbf{E}}</math> | + | Note that a [[kite]] has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is <math>\boxed{\textbf{E}}</math>. |
==See also== | ==See also== | ||
{{AHSME 50p box|year=1959|num-b=2|num-a=4}} | {{AHSME 50p box|year=1959|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
+ | [[Category:Introductory Geometry Problems]] |
Latest revision as of 13:07, 22 July 2024
Problem 3
If the diagonals of a quadrilateral are perpendicular to each other, the figure would always be included under the general classification:
Solution
Note that a kite has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is .
See also
1959 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.