Difference between revisions of "2003 AMC 12B Problems/Problem 24"
(hrmm.. my solution is actually completely incorrect, but I got the right answer) |
m (→Solution: typo) |
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\qquad\mathrm{(E)}\ 2004</math> | \qquad\mathrm{(E)}\ 2004</math> | ||
== Solution == | == Solution == | ||
+ | {{solution}} | ||
== See also == | == See also == |
Revision as of 18:18, 5 February 2008
Problem
Positive integers and
are chosen so that
, and the system of equations
![$2x + y = 2003 \quad$](http://latex.artofproblemsolving.com/7/0/6/706aa31c279b4f4744165bfddf5f8bd451518a57.png)
![$\quad y = |x-a| + |x-b| + |x-c|$](http://latex.artofproblemsolving.com/5/7/c/57c363455cd9e9bf8c2dceadb7298327d953e0bc.png)
has exactly one solution. What is the minimum value of ?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
2003 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 23 |
Followed by Problem 25 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |