Difference between revisions of "2024 AMC 8 Problems"

Revision as of 22:21, 17 December 2024

2024 AMC 8 (Answer Key) Printable versions: Wiki • AoPS Resources • PDF
Instructions This is a 25-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct. You will receive 1 point for each correct answer. There is no penalty for wrong answers. No aids are permitted other than plain scratch paper, writing utensils, ruler, and erasers. In particular, graph paper, compass, protractor, calculators, computers, smartwatches, and smartphones are not permitted. Rules Figures are not necessarily drawn to scale. You will have 40 minutes working time to complete the test.
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Problem 1

What is the ones digit of $222{,}222-22{,}222-2{,}222-222-22-2?$ $\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8$

Solution

Problem 2

What is the value of this expression in decimal form? $\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}$

$\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94$

Solution

Problem 3

Four squares of side length $4, 7, 9,$ and $10$ are arranged in increasing size order so that their left edges and bottom edges align. The squares alternate in color white-gray-white-gray, respectively, as shown in the figure. What is the area of the visible gray region in square units? $[asy] size(150); filldraw((0,0)--(10,0)--(10,10)--(0,10)--cycle,gray(0.7),linewidth(1)); filldraw((0,0)--(9,0)--(9,9)--(0,9)--cycle,white,linewidth(1)); filldraw((0,0)--(7,0)--(7,7)--(0,7)--cycle,gray(0.7),linewidth(1)); filldraw((0,0)--(4,0)--(4,4)--(0,4)--cycle,white,linewidth(1)); draw((11,0)--(11,4),linewidth(1)); draw((11,6)--(11,10),linewidth(1)); label("$10$",(11,5),fontsize(14pt)); draw((10.75,0)--(11.25,0),linewidth(1)); draw((10.75,10)--(11.25,10),linewidth(1)); draw((0,11)--(3,11),linewidth(1)); draw((5,11)--(9,11),linewidth(1)); draw((0,11.25)--(0,10.75),linewidth(1)); draw((9,11.25)--(9,10.75),linewidth(1)); label("$9$",(4,11),fontsize(14pt)); draw((-1,0)--(-1,1),linewidth(1)); draw((-1,3)--(-1,7),linewidth(1)); draw((-1.25,0)--(-0.75,0),linewidth(1)); draw((-1.25,7)--(-0.75,7),linewidth(1)); label("$7$",(-1,2),fontsize(14pt)); draw((0,-1)--(1,-1),linewidth(1)); draw((3,-1)--(4,-1),linewidth(1)); draw((0,-1.25)--(0,-.75),linewidth(1)); draw((4,-1.25)--(4,-.75),linewidth(1)); label("$4$",(2,-1),fontsize(14pt)); [/asy]$ $\textbf{(A)}\ 42 \qquad \textbf{(B)}\ 45\qquad \textbf{(C)}\ 49\qquad \textbf{(D)}\ 50\qquad \textbf{(E)}\ 52$

Solution

Problem 4

When Yunji added all the integers from $1$ to $9$ , she mistakenly left out a number. Her sum turned out to be a square number. What number did Yunji leave out?

$\textbf{(A) } 5\qquad\textbf{(B) } 6\qquad\textbf{(C) } 7\qquad\textbf{(D) } 8\qquad\textbf{(E) } 9$

Solution

Problem 5

Aaliyah rolls two standard 6-sided dice. She notices that the product of the two numbers rolled is a multiple of $6$ . Which of the following integers cannot be the sum of the two numbers?

$\textbf{(A) } 5\qquad\textbf{(B) } 6\qquad\textbf{(C) } 7\qquad\textbf{(D) } 8\qquad\textbf{(E) } 9$

Solution

Problem 6

Sergei skated around an ice rink, gliding along different paths. The gray lines in the figures below show four of the paths labeled $P$ , $Q$ , $R$ , and $S$ . What is the sorted order of the four paths from shortest to longest?

$\textbf{(A)}\ P,Q,R,S \qquad \textbf{(B)}\ P,R,S,Q \qquad \textbf{(C)}\ Q,S,P,R \qquad \textbf{(D)}\ R,P,S,Q \qquad \textbf{(E)}\ R,S,P,Q$

Solution

Problem 7

A $3\times 7$ rectangle is covered without overlap by 3 shapes of tiles: $2\times 2$ , $1\times 4$ , and $1\times 1$ , shown below. What is the minimum possible number of $1\times 1$ tiles used?

$\textbf{(A) } 1\qquad\textbf{(B) } 2\qquad\textbf{(C) } 3\qquad\textbf{(D) } 4\qquad\textbf{(E) } 5$

Solution

Problem 8

On Monday Taye has $$2$ . Every day, he either gains $$3$ or doubles the amount of money he had on the previous day. How many different dollar amounts could Taye have on Thursday, $3$ days later?

$\textbf{(A) } 3\qquad\textbf{(B) } 4\qquad\textbf{(C) } 5\qquad\textbf{(D) } 6\qquad\textbf{(E) } 7$

Solution

Problem 9

All the marbles in Maria's collection are red, green, or blue. Maria has half as many red marbles as green marbles and twice as many blue marbles as green marbles. Which of the following could be the total number of marbles in Maria's collection?

$\textbf{(A) } 24\qquad\textbf{(B) } 25\qquad\textbf{(C) } 26\qquad\textbf{(D) } 27\qquad\textbf{(E) } 28$

Solution

Problem 10

In January 1980 the Moana Loa Observation recorded carbon dioxide $(CO_2)$ levels of 338 ppm (parts per million). Over the years the average $CO_2$ reading has increased by about 1.515 ppm each year. What is the expected $CO_2$ level in ppm in January 2030? Round your answer to the nearest integer.

$\textbf{(A)}\ 399 \qquad \textbf{(B)}\ 414 \qquad \textbf{(C)}\ 420 \qquad \textbf{(D)}\ 444 \qquad \textbf{(E)}\ 459$

Solution

Problem 11

The coordinates of $\triangle ABC$ are $A(5,7)$ , $B(11,7)$ , and $C(3,y)$ , with $y>7$ . The area of $\triangle ABC$ is 12. What is the value of $y$ ?

$[asy] // Diagram inaccurate to prevent measuring with ruler. size(10cm); draw((3,10)--(11,7)--(5,7)--(3,10)); dot((5,7)); label("$A(5,7)$",(5,7),S); dot((11,7)); label("$B(11,7)$",(11,7),S); dot((3,10)); label("$C(3,y)$",(3,10),NW); // Problem 11: put on here by Andrei.martynau [/asy]$

$\textbf{(A) }8\qquad\textbf{(B) }9\qquad\textbf{(C) }10\qquad\textbf{(D) }11\qquad \textbf{(E) }12$

Solution

Problem 12

Rohan keeps a total of $90$ guppies in $4$ fish tanks.

There is $1$ more guppy in the $2$ nd tank than the $1$ st tank.

There are $2$ more guppies in the 3rd tank than the $2$ nd tank.

There are $3$ more guppies in the 4th tank than the $3$ rd tank.

How many guppies are in the $4$ th tank?

$\textbf{(A)}\ 20 \qquad \textbf{(B)}\ 21 \qquad \textbf{(C)}\ 23 \qquad \textbf{(D)}\ 24 \qquad \textbf{(E)}\ 26$

Solution

Problem 13

Buzz Bunny is hopping up and down a set of stairs, one step at a time. In how many ways can Buzz Bunny start on the ground, make a sequence of $6$ hops, and end up back on the ground? (For example, one sequence of hops is up-up-down-down-up-down.)

$[asy] /* AMC8 P13 2024, revised by Teacher David */ /** * This Geometry Artwork/Graph is designed using GeoSketch v1.0, * a free software tool created by Tina Yan, William Zhong, and * Teacher David. * * For more information, please refer to * https://geosketch.org (under construction) */ defaultpen(linewidth(1pt)); unitsize(0.3pt); import graph; /** * Define a quadratic bezier curve function. */ typedef pair quad_bezier(real t); quad_bezier fungen (pair a, pair b, pair c) { return new pair (real t) { real x = (1-t)*(1-t)*a.x + 2*(1-t)*t*b.x + t*t*c.x; real y = (1-t)*(1-t)*a.y + 2*(1-t)*t*b.y + t*t*c.y; return (x,y); }; } quad_bezier qb0 = fungen((293,243),(237,276),(239,310)); draw(graph(qb0, 0,1)); quad_bezier qb1 = fungen((239,310),(274,301),(295,254)); draw(graph(qb1, 0,1)); quad_bezier qb2 = fungen((266,294),(260,309),(266,323)); draw(graph(qb2, 0,1)); quad_bezier qb3 = fungen((266,323),(294,311),(302,257)); draw(graph(qb3, 0,1)); quad_bezier qb4 = fungen((333,258),(341,249),(348,244)); draw(graph(qb4, 0,1)); quad_bezier qb5 = fungen((348,244),(355,241),(351,234)); draw(graph(qb5, 0,1)); quad_bezier qb6 = fungen((351,234),(348,226),(338,226)); draw(graph(qb6, 0,1)); quad_bezier qb7 = fungen((351,234),(350,219),(321,208)); draw(graph(qb7, 0,1)); quad_bezier qb8 = fungen((260,247),(135,293),(137,170)); draw(graph(qb8, 0,1)); quad_bezier qb9 = fungen((122,161),(132,147),(148,144)); draw(graph(qb9, 0,1)); quad_bezier qb10 = fungen((148,144),(176,155),(204,146)); draw(graph(qb10, 0,1)); quad_bezier qb11 = fungen((204,146),(216,141),(235,137)); draw(graph(qb11, 0,1)); quad_bezier qb12 = fungen((228,156),(208,160),(188,161)); draw(graph(qb12, 0,1)); quad_bezier qb13 = fungen((319,214),(313,174),(283,168)); draw(graph(qb13, 0,1)); quad_bezier qb14 = fungen((228,156),(242,158),(247,171)); draw(graph(qb14, 0,1)); quad_bezier qb15 = fungen((245,181),(250,158),(266,143)); draw(graph(qb15, 0,1)); quad_bezier qb16 = fungen((266,143),(287,134),(298,135)); draw(graph(qb16, 0,1)); quad_bezier qb17 = fungen((298,135),(309,143),(300,148)); draw(graph(qb17, 0,1)); quad_bezier qb18 = fungen((300,148),(272,150),(270,175)); draw(graph(qb18, 0,1)); quad_bezier qb19 = fungen((282,177),(274,158),(300,148)); draw(graph(qb19, 0,1)); draw(arc((317.8948497854077,245.25965665236052), 19.760615163024095, 143.54947493250435, 40.14574559948477)); draw(arc((282.65584415584414,295.7857142857143), 53.78971270402217, -78.91253214600312, -114.90992209204622)); draw(arc((127.7,168.5), 9.420191080864546, 9.162347045721713, 232.7651660184253)); draw(arc((229.125,145.625), 10.435815732370902, -55.73889710090544, 96.1886159632416)); draw(arc((186.26470588235293,181.5), 20.573313920580237, -85.1615330431756, 85.1615330431756)); filldraw(ellipse((314,235), 13.0, 10.04987562112089), rgb(254,255,255), black); filldraw(rotate(14.036243467926468,(315,251))*ellipse((315,235), 9.219544457292887, 8.246211251235321), rgb(0,0,0), black); pair o = (400,190); real len=80; real height=56; for (int i=0; i<4; ++i) { pair a = (i*len, i*height); path p = a -- a+(len,0) -- a+(len, height); draw(shift(o)*p); } path p = (0,0)--(0,-height)--(4*len,-height); draw(shift(o)*p); [/asy]$

$\textbf{(A)}\ 4 \qquad \textbf{(B)}\ 5 \qquad \textbf{(C)}\ 6 \qquad \textbf{(D)}\ 8 \qquad \textbf{(E)}\ 12$

Solution

Problem 14

The one-way routes connecting towns $A,M,C,X,Y,$ and $Z$ are shown in the figure below (not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance from A to Z in kilometers?

$[asy] /* AMC8 P14 2024, by NUMANA: BUI VAN HIEU */ import graph; unitsize(2cm); real r=0.25; // Define the nodes and their positions pair[] nodes = { (0,0), (2,0), (1,1), (3,1), (4,0), (6,0) }; string[] labels = { "A", "M", "X", "Y", "C", "Z" }; // Draw the nodes as circles with labels for(int i = 0; i < nodes.length; ++i) { draw(circle(nodes[i], r)); label("$" + labels[i] + "$", nodes[i]); } // Define the edges with their node indices and labels int[][] edges = { {0, 1}, {0, 2}, {2, 1}, {2, 3}, {1, 3}, {1, 4}, {3, 4}, {4, 5}, {3, 5} }; string[] edgeLabels = { "8", "5", "2", "10", "6", "14", "5", "10", "17" }; pair[] edgeLabelsPos = { S, SE, SW, S, SE, S, SW, S, NE}; // Draw the edges with labels for (int i = 0; i < edges.length; ++i) { pair start = nodes[edges[i][0]]; pair end = nodes[edges[i][1]]; draw(start + r*dir(end-start) -- end-r*dir(end-start), Arrow); label("$" + edgeLabels[i] + "$", midpoint(start -- end), edgeLabelsPos[i]); } // Draw the curved edge with label draw(nodes[1]+r * dir(-45)..controls (3, -0.75) and (5, -0.75)..nodes[5]+r * dir(-135), Arrow); label("$25$", midpoint(nodes[1]..controls (3, -0.75) and (5, -0.75)..nodes[5]), 2S); [/asy]$

$\textbf{(A)}\ 28 \qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 30 \qquad \textbf{(D)}\ 31 \qquad \textbf{(E)}\ 32$

Solution

Problem 15

Let the letters $F$ , $L$ , $Y$ , $B$ , $U$ , $G$ represent distinct digits. Suppose $\underline{F}~\underline{L}~\underline{Y}~\underline{F}~\underline{L}~\underline{Y}$ is the greatest number that satisfies the equation

$8\cdot\underline{F}~\underline{L}~\underline{Y}~\underline{F}~\underline{L}~\underline{Y}=\underline{B}~\underline{U}~\underline{G}~\underline{B}~\underline{U}~\underline{G}.$

What is the value of $\underline{F}~\underline{L}~\underline{Y}+\underline{B}~\underline{U}~\underline{G}$ ?

$\textbf{(A)}\ 1089 \qquad \textbf{(B)}\ 1098 \qquad \textbf{(C)}\ 1107 \qquad \textbf{(D)}\ 1116 \qquad \textbf{(E)}\ 1125$

Solution

Problem 16

Minh enters the numbers $1$ through $81$ into the cells of a $9 \times 9$ grid in some order. She calculates the product of the numbers in each row and column. What is the least number of rows and columns that could have a product divisible by $3$ ?

$\textbf{(A) } 8\qquad\textbf{(B) } 9\qquad\textbf{(C) } 10\qquad\textbf{(D) } 11\qquad\textbf{(E) } 12$

Solution

Problem 17

A chess king is said to attack all squares one step away from it (basically any square right next to it in any direction), horizontally, vertically, or diagonally. For instance, a king on the center square of a 3 x 3 grid attacks all 8 other squares, as shown below. Suppose a white king and a black king are placed on different squares of 3 x 3 grid so that they do not attack each other. In how many ways can this be done?

$[asy] /* AMC8 P17 2024, revised by Teacher David */ unitsize(29pt); import math; add(grid(3,3)); pair [] a = {(0.5,0.5), (0.5, 1.5), (0.5, 2.5), (1.5, 2.5), (2.5,2.5), (2.5,1.5), (2.5,0.5), (1.5,0.5)}; for (int i=0; i<a.length; ++i) { pair x = (1.5,1.5) + 0.4*dir(225-45*i); draw(x -- a[i], arrow=EndArrow()); } label("$K$", (1.5,1.5)); [/asy]$

$\textbf{(A)}\ 20 \qquad \textbf{(B)}\ 24 \qquad \textbf{(C)}\ 27 \qquad \textbf{(D)}\ 28 \qquad \textbf{(E)}\ 32$

Solution

Problem 18

Three concentric circles centered at $O$ have radii of $1$ , $2$ , and $3$ . Points $B$ and $C$ lie on the largest circle. The region between the two smaller circles is shaded, as is the portion of the region between the two larger circles bounded by central angle $BOC$ , as shown in the figure below. Suppose the shaded and unshaded regions are equal in area. What is the measure of $\angle{BOC}$ in degrees?

$[asy] size(100); import graph; draw(circle((0,0),3)); real radius = 3; real angleStart = -54; // starting angle of the sector real angleEnd = 54; // ending angle of the sector label("$O$",(0,0),W); pair O = (0, 0); filldraw(arc(O, radius, angleStart, angleEnd)--O--cycle, lightgray); filldraw(circle((0,0),2),lightgray); filldraw(circle((0,0),1),white); draw((1.763,2.427)--(0,0)--(1.763,-2.427)); label("$B$",(1.763,2.427),NE); label("$C$",(1.763,-2.427),SE); [/asy]$

$\textbf{(A)}\ 108 \qquad \textbf{(B)}\ 120 \qquad \textbf{(C)}\ 135 \qquad \textbf{(D)}\ 144 \qquad \textbf{(E)}\ 150$

Solution

Problem 19

Jordan owns 15 pairs of sneakers. Three fifths of the pairs are red and the rest are white. Two thirds of the pairs are high-top and the rest are low-top. The red high-top sneakers make up a fraction of the collection. What is the least possible value of this fraction?

$\textbf{(A) } 0\qquad\textbf{(B) } \dfrac{1}{5} \qquad\textbf{(C) } \dfrac{4}{15} \qquad\textbf{(D) } \dfrac{1}{3} \qquad\textbf{(E) } \dfrac{2}{5}$

Solution

Problem 20

Any three vertices of the cube $PQRSTUVW,$ shown in the figure below, can be connected to form a triangle. $($ For example, vertices $P, Q,$ and $R$ can be connected to form $\triangle{PQR}.)$ How many of these triangles are equilateral and contain $P$ as a vertex?

$[asy] unitsize(4); pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0); draw(W--V); draw(V--Q); draw(Q--P); draw(P--W); draw(T--U); draw(U--R); draw(R--S); draw(S--T); draw(W--T); draw(P--S); draw(V--U); draw(Q--R); dot(P); dot(Q); dot(R); dot(S); dot(T); dot(U); dot(V); dot(W); label("$P$",P,NW); label("$Q$",Q,NW); label("$R$",R,NE); label("$S$",S,N); label("$T$",T,NE); label("$U$",U,NE); label("$V$",V,SE); label("$W$",W,SW); [/asy]$

$\textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }2\qquad\textbf{(D) }3\qquad\textbf{(E) }6$

Solution

Problem 21

A group of frogs (called an army) is living in a tree. A frog turns green when in the shade and turns yellow when in the sun. Initially, the ratio of green to yellow frogs was $3 : 1$ . Then $3$ green frogs moved to the sunny side and $5$ yellow frogs moved to the shady side. Now the ratio is $4 : 1$ . What is the difference between the number of green frogs and the number of yellow frogs now?

$\textbf{(A) } 10\qquad\textbf{(B) } 12\qquad\textbf{(C) } 16\qquad\textbf{(D) } 20\qquad\textbf{(E) } 24$

Solution

Problem 22

A roll of tape is $4$ inches in diameter and is wrapped around a ring that is $2$ inches in diameter. A cross section of the tape is shown in the figure below. The tape is $0.015$ inches thick. If the tape is completely unrolled, approximately how long would it be? Round your answer to the nearest $100$ inches.

$[asy] /* AMC8 P22 2024, revised by Teacher David */ size(150); pair o = (0,0); real r1 = 1; real r2 = 2; filldraw(circle(o, r2), mediumgray, linewidth(1pt)); filldraw(circle(o, r1), white, linewidth(1pt)); draw((-2,-2.6)--(-2,-2.4)); draw((2,-2.6)--(2,-2.4)); draw((-2,-2.5)--(2,-2.5), L=Label("4 in.")); draw((-1,0)--(1,0), L=Label("2 in.", align=(0,1)), arrow=Arrows()); draw((2,0)--(2,-1.3), linewidth(1pt)); [/asy]$

$\textbf{(A) } 300\qquad\textbf{(B) } 600\qquad\textbf{(C) } 1200\qquad\textbf{(D) } 1500\qquad\textbf{(E) } 1800$

Solution

Problem 23

Rodrigo has a very large sheet of graph paper. First he draws a line segment connecting point $(0,4)$ to point $(2,0)$ and colors the $4$ cells whose interiors intersect the segment, as shown below. Next Rodrigo draws a line segment connecting point $(2000,3000)$ to point $(5000,8000)$ . How many cells will he color this time?

$[asy] filldraw((0,4)--(1,4)--(1,3)--(0,3)--cycle, gray(.75), gray(.5)+linewidth(1)); filldraw((0,3)--(1,3)--(1,2)--(0,2)--cycle, gray(.75), gray(.5)+linewidth(1)); filldraw((1,2)--(2,2)--(2,1)--(1,1)--cycle, gray(.75), gray(.5)+linewidth(1)); filldraw((1,1)--(2,1)--(2,0)--(1,0)--cycle, gray(.75), gray(.5)+linewidth(1)); draw((-1,5)--(-1,-1),gray(.9)); draw((0,5)--(0,-1),gray(.9)); draw((1,5)--(1,-1),gray(.9)); draw((2,5)--(2,-1),gray(.9)); draw((3,5)--(3,-1),gray(.9)); draw((4,5)--(4,-1),gray(.9)); draw((5,5)--(5,-1),gray(.9)); draw((-1,5)--(5, 5),gray(.9)); draw((-1,4)--(5,4),gray(.9)); draw((-1,3)--(5,3),gray(.9)); draw((-1,2)--(5,2),gray(.9)); draw((-1,1)--(5,1),gray(.9)); draw((-1,0)--(5,0),gray(.9)); draw((-1,-1)--(5,-1),gray(.9)); dot((0,4)); label("$(0,4)$",(0,4),NW); dot((2,0)); label("$(2,0)$",(2,0),SE); draw((0,4)--(2,0)); draw((-1,0) -- (5,0), arrow=Arrow); draw((0,-1) -- (0,5), arrow=Arrow); [/asy]$

$\textbf{(A) }6000\qquad\textbf{(B) }6500\qquad\textbf{(C) }7000\qquad\textbf{(D) }7500\qquad\textbf{(E) }8000$

Solution

Problem 24

Jean has made a piece of stained glass art in the shape of two mountains, as shown in the figure below. One mountain peak is $8$ feet high while the other peak is $12$ feet high. Each peak forms a $90^\circ$ angle, and the straight sides form a $45^\circ$ angle with the ground. The artwork has an area of $183$ square feet. The sides of the mountain meet at an intersection point near the center of the artwork, $h$ feet above the ground. What is the value of $h?$

$[asy] unitsize(.3cm); filldraw((0,0)--(8,8)--(11,5)--(18,12)--(30,0)--cycle,gray(0.7),linewidth(1)); draw((-1,0)--(-1,8),linewidth(.75)); draw((-1.4,0)--(-.6,0),linewidth(.75)); draw((-1.4,8)--(-.6,8),linewidth(.75)); label("$8$",(-1,4),W); label("$12$",(31,6),E); draw((-1,8)--(8,8),dashed); draw((31,0)--(31,12),linewidth(.75)); draw((30.6,0)--(31.4,0),linewidth(.75)); draw((30.6,12)--(31.4,12),linewidth(.75)); draw((31,12)--(18,12),dashed); label("$45^{\circ}$",(.75,0),NE,fontsize(10pt)); label("$45^{\circ}$",(29.25,0),NW,fontsize(10pt)); draw((8,8)--(7.5,7.5)--(8,7)--(8.5,7.5)--cycle); draw((18,12)--(17.5,11.5)--(18,11)--(18.5,11.5)--cycle); draw((11,5)--(11,0),dashed); label("$h$",(11,2.5),E); [/asy]$

$\textbf{(A)}\ 4 \qquad \textbf{(B)}\ 5 \qquad \textbf{(C)}\ 4\sqrt{2} \qquad \textbf{(D)}\ 6 \qquad \textbf{(E)}\ 5\sqrt{2}$

Solution

Problem 25

A small airplane has $4$ rows of seats with $3$ seats in each row. Eight passengers have boarded the plane and are distributed randomly among the seats. A married couple is next to board. What is the probability there will be $2$ adjacent seats in the same row for the couple?

$\textbf{(A)}\ \dfrac{8}{15} \qquad \textbf{(B)}\ \dfrac{32}{55} \qquad \textbf{(C)}\ \dfrac{20}{33} \qquad \textbf{(D)}\ \dfrac{34}{55} \qquad \textbf{(E)}\ \dfrac{8}{11}$

Solution

2024 AMC 8 (Problems • Answer Key • Resources)
Preceded by 2023 AMC 8	Followed by 2025 AMC 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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Difference between revisions of "2024 AMC 8 Problems"

Revision as of 22:21, 17 December 2024

Contents

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

See Also

@@ Line 1: / Line 1: @@
 {{AMC8 Problems|year=2024|}}
-==Problem 1==   One behalf of the AoPS team we have came to notice that these questions are editable as our dev team in on break at the moment this bug will not be fixed. Everyone who has written something no matter what the reason has broken the code of conduct witch was signed in the creation of your account. By writing something here your account will be banned(In the next 48 hours) and you will be banned from taking any future AoPS competitions. Our team here at AoPS has also came to notice that the AMC-8 2024 answers have been leaked as this is changing the results all over the country we will not be counting this test and will be creating another one to take its place. We have also noticed that there is one individual trying to stop the cheating of AMC-8 and thank you for including some light hearted jokes to help lighten the mood. On the behalf of the AoPS team we thank you for reading this message.
 ==Problem 1==
- One behalf of the AoPS team we have came to notice that these questions are editable as our dev team in on break at the moment this bug will not be fixed. Everyone who has written something no matter what the reason has broken the code of conduct witch was signed in the creation of your account. By writing something here your account will be banned(In the next 48 hours) and you will be banned from taking any future AoPS competitions. Our team here at AoPS has also came to notice that the AMC-8 2024 answers have been leaked as this is changing the results all over the country we will not be counting this test and will be creating another one to take its place. We have also noticed that there is one individual trying to stop the cheating of AMC-8 and thank you for including some light hearted jokes to help lighten the mood. On the behalf of the AoPS team we thank you for reading this message.
+What is the ones digit of <cmath>222{,}222-22{,}222-2{,}222-222-22-2?</cmath>
+<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math>
+[[2024 AMC 8 Problems/Problem 1|Solution]]
+==Problem 2==
+What is the value of this expression in decimal form?
+<cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath>
+<math>\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94</math>
+[[2024 AMC 8 Problems/Problem 2|Solution]]
+==Problem 3 ==
+Four squares of side length <math>4, 7, 9,</math> and <math>10</math> are arranged in increasing size order so that their left edges and bottom edges align. The squares alternate in color white-gray-white-gray, respectively, as shown in the figure. What is the area of the visible gray region in square units?
+<asy>
+size(150);
+filldraw((0,0)--(10,0)--(10,10)--(0,10)--cycle,gray(0.7),linewidth(1));
+filldraw((0,0)--(9,0)--(9,9)--(0,9)--cycle,white,linewidth(1));
+filldraw((0,0)--(7,0)--(7,7)--(0,7)--cycle,gray(0.7),linewidth(1));
+filldraw((0,0)--(4,0)--(4,4)--(0,4)--cycle,white,linewidth(1));
+draw((11,0)--(11,4),linewidth(1));
+draw((11,6)--(11,10),linewidth(1));
+label("$10$",(11,5),fontsize(14pt));
+draw((10.75,0)--(11.25,0),linewidth(1));
+draw((10.75,10)--(11.25,10),linewidth(1));
+draw((0,11)--(3,11),linewidth(1));
+draw((5,11)--(9,11),linewidth(1));
+draw((0,11.25)--(0,10.75),linewidth(1));
+draw((9,11.25)--(9,10.75),linewidth(1));
+label("$9$",(4,11),fontsize(14pt));
+draw((-1,0)--(-1,1),linewidth(1));
+draw((-1,3)--(-1,7),linewidth(1));
+draw((-1.25,0)--(-0.75,0),linewidth(1));
+draw((-1.25,7)--(-0.75,7),linewidth(1));
+label("$7$",(-1,2),fontsize(14pt));
+draw((0,-1)--(1,-1),linewidth(1));
+draw((3,-1)--(4,-1),linewidth(1));
+draw((0,-1.25)--(0,-.75),linewidth(1));
+draw((4,-1.25)--(4,-.75),linewidth(1));
+label("$4$",(2,-1),fontsize(14pt));
+</asy>
+<math>\textbf{(A)}\ 42 \qquad \textbf{(B)}\ 45\qquad \textbf{(C)}\ 49\qquad \textbf{(D)}\ 50\qquad \textbf{(E)}\ 52</math>
+[[2024 AMC 8 Problems/Problem 3|Solution]]
+==Problem 4==
+When Yunji added all the integers from <math>1</math> to <math>9</math>, she mistakenly left out a number. Her sum turned out to be a square number. What number did Yunji leave out?
+<math>\textbf{(A) } 5\qquad\textbf{(B) } 6\qquad\textbf{(C) } 7\qquad\textbf{(D) } 8\qquad\textbf{(E) } 9</math>
+[[2024 AMC 8 Problems/Problem 4|Solution]]
+==Problem 5==
+Aaliyah rolls two standard 6-sided dice. She notices that the product of the two numbers rolled is a multiple of <math>6</math>. Which of the following integers cannot be the sum of the two numbers?
+<math>\textbf{(A) } 5\qquad\textbf{(B) } 6\qquad\textbf{(C) } 7\qquad\textbf{(D) } 8\qquad\textbf{(E) } 9</math>
+[[2024 AMC 8 Problems/Problem 5|Solution]]
+==Problem 6==
+Sergei skated around an ice rink, gliding along different paths. The gray lines in the figures below show four of the paths labeled <math>P</math>, <math>Q</math>, <math>R</math>, and <math>S</math>. What is the sorted order of the four paths from shortest to longest?
+[[Image:2024_AMC_8-Problem_6.png|center|500px]]
+<math>\textbf{(A)}\ P,Q,R,S \qquad \textbf{(B)}\ P,R,S,Q \qquad \textbf{(C)}\ Q,S,P,R \qquad \textbf{(D)}\ R,P,S,Q \qquad \textbf{(E)}\ R,S,P,Q</math>
+[[2024 AMC 8 Problems/Problem 6|Solution]]
+==Problem 7==
+A <math>3\times 7</math> rectangle is covered without overlap by 3 shapes of tiles: <math>2\times 2</math>, <math>1\times 4</math>, and <math>1\times 1</math>, shown below. What is the minimum possible number of <math>1\times 1</math> tiles used?
+[[File:2024-AMC8-q7.png|center|caption]]
+<math>\textbf{(A) } 1\qquad\textbf{(B) } 2\qquad\textbf{(C) } 3\qquad\textbf{(D) } 4\qquad\textbf{(E) } 5</math>
+[[2024 AMC 8 Problems/Problem 7|Solution]]
+==Problem 8==
+On Monday Taye has <math>\$2</math>. Every day, he either gains <math>\$3</math> or doubles the amount of money he had on the previous day. How many different dollar amounts could Taye have on Thursday, <math>3</math> days later?
+<math>\textbf{(A) } 3\qquad\textbf{(B) } 4\qquad\textbf{(C) } 5\qquad\textbf{(D) } 6\qquad\textbf{(E) } 7</math>
+[[2024 AMC 8 Problems/Problem 8|Solution]]
+==Problem 9==
+All the marbles in Maria's collection are red, green, or blue. Maria has half as many red marbles as green marbles and twice as many blue marbles as green marbles. Which of the following could be the total number of marbles in Maria's collection?
+<math>\textbf{(A) } 24\qquad\textbf{(B) } 25\qquad\textbf{(C) } 26\qquad\textbf{(D) } 27\qquad\textbf{(E) } 28</math>
+[[2024 AMC 8 Problems/Problem 9|Solution]]
+==Problem 10==
+In January 1980 the Moana Loa Observation recorded carbon dioxide <math>(CO_2)</math> levels of 338 ppm (parts per million). Over the years the average <math>CO_2</math> reading has increased by about 1.515 ppm each year. What is the expected <math>CO_2</math> level in ppm in January 2030? Round your answer to the nearest integer.
+<math>\textbf{(A)}\ 399 \qquad \textbf{(B)}\ 414 \qquad \textbf{(C)}\ 420 \qquad \textbf{(D)}\ 444 \qquad \textbf{(E)}\ 459</math>
+[[2024 AMC 8 Problems/Problem 10|Solution]]
+==Problem 11==
+The coordinates of <math>\triangle ABC</math> are <math>A(5,7)</math>, <math>B(11,7)</math>, and <math>C(3,y)</math>, with <math>y>7</math>. The area of <math>\triangle ABC</math> is 12. What is the value of <math>y</math>?
+<asy>
+// Diagram inaccurate to prevent measuring with ruler.
+size(10cm);
+draw((3,10)--(11,7)--(5,7)--(3,10));
+dot((5,7));
+label("$A(5,7)$",(5,7),S);
+dot((11,7));
+label("$B(11,7)$",(11,7),S);
+dot((3,10));
+label("$C(3,y)$",(3,10),NW);
+// Problem 11: put on here by Andrei.martynau
+</asy>
+<math>\textbf{(A) }8\qquad\textbf{(B) }9\qquad\textbf{(C) }10\qquad\textbf{(D) }11\qquad \textbf{(E) }12</math>
+[[2024 AMC 8 Problems/Problem 11|Solution]]
+==Problem 12==
+Rohan keeps a total of <math>90</math> guppies in <math>4</math> fish tanks.
+*There is <math>1</math> more guppy in the <math>2</math>nd tank than the <math>1</math>st tank.
+*There are <math>2</math> more guppies in the 3rd tank than the <math>2</math>nd tank.
+*There are <math>3</math> more guppies in the 4th tank than the <math>3</math>rd tank.
+How many guppies are in the <math>4</math>th tank?
+<math>\textbf{(A)}\ 20 \qquad \textbf{(B)}\ 21 \qquad \textbf{(C)}\ 23 \qquad \textbf{(D)}\ 24 \qquad \textbf{(E)}\ 26</math>
+[[2024 AMC 8 Problems/Problem 12|Solution]]
 ==Problem 13==
+Buzz Bunny is hopping up and down a set of stairs, one step at a time. In how many ways can Buzz Bunny start on the ground, make a sequence of <math>6</math> hops, and end up back on the ground?
+(For example, one sequence of hops is up-up-down-down-up-down.)
+<asy>
+/* AMC8 P13 2024, revised by Teacher David */
+/**
+ * This Geometry Artwork/Graph is designed using GeoSketch v1.0,
+ * a free software tool created by Tina Yan, William Zhong, and
+ * Teacher David.
+ *
+ * For more information, please refer to
+ *   https://geosketch.org (under construction)
+ */
+defaultpen(linewidth(1pt));
+unitsize(0.3pt);
+import graph;
+/**
+ * Define a quadratic bezier curve function.
+ */
+typedef pair quad_bezier(real t);
+quad_bezier fungen (pair a, pair b, pair c) {
+  return new pair (real t) {
+    real x = (1-t)*(1-t)*a.x + 2*(1-t)*t*b.x + t*t*c.x;
+    real y = (1-t)*(1-t)*a.y + 2*(1-t)*t*b.y + t*t*c.y;
+    return (x,y);
+  };
+}
+quad_bezier qb0 = fungen((293,243),(237,276),(239,310));
+draw(graph(qb0, 0,1));
+quad_bezier qb1 = fungen((239,310),(274,301),(295,254));
+draw(graph(qb1, 0,1));
+quad_bezier qb2 = fungen((266,294),(260,309),(266,323));
+draw(graph(qb2, 0,1));
+quad_bezier qb3 = fungen((266,323),(294,311),(302,257));
+draw(graph(qb3, 0,1));
+quad_bezier qb4 = fungen((333,258),(341,249),(348,244));
+draw(graph(qb4, 0,1));
+quad_bezier qb5 = fungen((348,244),(355,241),(351,234));
+draw(graph(qb5, 0,1));
+quad_bezier qb6 = fungen((351,234),(348,226),(338,226));
+draw(graph(qb6, 0,1));
+quad_bezier qb7 = fungen((351,234),(350,219),(321,208));
+draw(graph(qb7, 0,1));
+quad_bezier qb8 = fungen((260,247),(135,293),(137,170));
+draw(graph(qb8, 0,1));
+quad_bezier qb9 = fungen((122,161),(132,147),(148,144));
+draw(graph(qb9, 0,1));
+quad_bezier qb10 = fungen((148,144),(176,155),(204,146));
+draw(graph(qb10, 0,1));
+quad_bezier qb11 = fungen((204,146),(216,141),(235,137));
+draw(graph(qb11, 0,1));
+quad_bezier qb12 = fungen((228,156),(208,160),(188,161));
+draw(graph(qb12, 0,1));
+quad_bezier qb13 = fungen((319,214),(313,174),(283,168));
+draw(graph(qb13, 0,1));
+quad_bezier qb14 = fungen((228,156),(242,158),(247,171));
+draw(graph(qb14, 0,1));
+quad_bezier qb15 = fungen((245,181),(250,158),(266,143));
+draw(graph(qb15, 0,1));
+quad_bezier qb16 = fungen((266,143),(287,134),(298,135));
+draw(graph(qb16, 0,1));
+quad_bezier qb17 = fungen((298,135),(309,143),(300,148));
+draw(graph(qb17, 0,1));
+quad_bezier qb18 = fungen((300,148),(272,150),(270,175));
+draw(graph(qb18, 0,1));
+quad_bezier qb19 = fungen((282,177),(274,158),(300,148));
+draw(graph(qb19, 0,1));
+draw(arc((317.8948497854077,245.25965665236052), 19.760615163024095, 143.54947493250435, 40.14574559948477));
+draw(arc((282.65584415584414,295.7857142857143), 53.78971270402217, -78.91253214600312, -114.90992209204622));
+draw(arc((127.7,168.5), 9.420191080864546, 9.162347045721713, 232.7651660184253));
+draw(arc((229.125,145.625), 10.435815732370902, -55.73889710090544, 96.1886159632416));
+draw(arc((186.26470588235293,181.5), 20.573313920580237, -85.1615330431756, 85.1615330431756));
+filldraw(ellipse((314,235), 13.0, 10.04987562112089), rgb(254,255,255), black);
+filldraw(rotate(14.036243467926468,(315,251))*ellipse((315,235), 9.219544457292887, 8.246211251235321),
+	rgb(0,0,0), black);
-A finite set <math>S</math> of positive integers has the property that, for each <math>s\in S</math>, and each positive integer divisor <math>d</math> of <math>s</math>, there exists a unique element <math>t \in S</math> satisfying <math>\gcd(s,t)=d</math> (the elements <math>s</math> and <math>t</math> could be equal).
+pair o = (400,190);
+real len=80;
+real height=56;
+for (int i=0; i<4; ++i) {
+    pair a = (i*len, i*height);
+    path p = a -- a+(len,0) -- a+(len, height);
+    draw(shift(o)*p);
+}
+path p = (0,0)--(0,-height)--(4*len,-height);
+draw(shift(o)*p);
+</asy>
-Given this information, find all possible values for the number of elements of <math>S</math>. (source: 2021 USAMO)
-now that you read this problem you have to do it without looking at the solution or else... let's just say bad things will happen
+<math>\textbf{(A)}\ 4 \qquad \textbf{(B)}\ 5 \qquad \textbf{(C)}\ 6 \qquad \textbf{(D)}\ 8 \qquad \textbf{(E)}\ 12</math>
+[[2024 AMC 8 Problems/Problem 13|Solution]]
 ==Problem 14==
-Let k >/ 2 be an integer. Find the smallest integer <math>n</math> >/ k + 1 with the property that
+The one-way routes connecting towns <math>A,M,C,X,Y,</math> and <math>Z</math> are shown in the figure below (not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance from A to Z in kilometers?
-there exists a set of n distinct real numbers such that each of its elements can be written as a
-sum of k other distinct elements of the set. (Source: IMO Shortlist Slovakia)
-(A) <math>n=k</math> + 3   (B) <math>n=k</math> - 3   (C) <math>n=k</math> + 4   (D) <math>n=k</math>   (E) <math>n=k</math> + 5
+<asy>
+/* AMC8 P14 2024, by NUMANA: BUI VAN HIEU */
+import graph;
+unitsize(2cm);
+real r=0.25;
+// Define the nodes and their positions
+pair[] nodes = { (0,0), (2,0), (1,1), (3,1), (4,0), (6,0) };
+string[] labels = { "A", "M", "X", "Y", "C", "Z" };
+// Draw the nodes as circles with labels
+for(int i = 0; i < nodes.length; ++i) {
+    draw(circle(nodes[i], r));
+    label("$" + labels[i] + "$", nodes[i]);
+}
+// Define the edges with their node indices and labels
+int[][] edges = { {0, 1}, {0, 2}, {2, 1}, {2, 3}, {1, 3}, {1, 4}, {3, 4}, {4, 5}, {3, 5} };
+string[] edgeLabels = { "8", "5", "2", "10", "6", "14", "5", "10", "17" };
+pair[] edgeLabelsPos = { S, SE, SW, S, SE, S, SW, S, NE};
+// Draw the edges with labels
+for (int i = 0; i < edges.length; ++i) {
+    pair start = nodes[edges[i][0]];
+    pair end = nodes[edges[i][1]];
+    draw(start + r*dir(end-start) -- end-r*dir(end-start), Arrow);
+    label("$" + edgeLabels[i] + "$", midpoint(start -- end),  edgeLabelsPos[i]);
+}
+// Draw the curved edge with label
+draw(nodes[1]+r * dir(-45)..controls (3, -0.75) and (5, -0.75)..nodes[5]+r * dir(-135), Arrow);
+label("$25$", midpoint(nodes[1]..controls (3, -0.75) and (5, -0.75)..nodes[5]), 2S);
+</asy>
+<math>\textbf{(A)}\ 28 \qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 30 \qquad \textbf{(D)}\ 31 \qquad \textbf{(E)}\ 32</math>
+[[2024 AMC 8 Problems/Problem 14|Solution]]
 ==Problem 15==
-Let <math>D</math> be an interior point of the acute triangle <math>ABC</math> with <math>AB > AC</math> so that <math>\angle DAB= \angle CAD</math>. The point <math>E</math> on the segment <math>AC</math> satisfies <math>\angle ADE= \angle BCD</math>, the point <math>F</math> on the segment <math>AB</math> satisfies <math>\angle FDA= \angle DBC</math>, and the point <math>X</math> on the line <math>AC</math> satisfies <math>CX=BX</math>. Let <math>O_1</math> and <math>O_2</math> be the circumcentres of the triangles <math>ADC</math> and <math>EXD</math> respectively. Prove that the lines <math>BC</math>, <math>EF</math>, and <math>O_1 O_2</math> are concurrent. (source: 2021 IMO)
+Let the letters <math>F</math>,<math>L</math>,<math>Y</math>,<math>B</math>,<math>U</math>,<math>G</math> represent distinct digits. Suppose <math>\underline{F}~\underline{L}~\underline{Y}~\underline{F}~\underline{L}~\underline{Y}</math> is the greatest number that satisfies the equation
-now go do this problem WITHOUT THE SOLUTION as a punishment for trying to cheat
+<cmath>8\cdot\underline{F}~\underline{L}~\underline{Y}~\underline{F}~\underline{L}~\underline{Y}=\underline{B}~\underline{U}~\underline{G}~\underline{B}~\underline{U}~\underline{G}.</cmath>
+What is the value of <math>\underline{F}~\underline{L}~\underline{Y}+\underline{B}~\underline{U}~\underline{G}</math>?
-What is the value of 1, assuming that 1=1, but 1= 3(4x^2-7x+5) - 2(5x^2-9x-3)=6x
+<math>\textbf{(A)}\ 1089 \qquad \textbf{(B)}\ 1098 \qquad \textbf{(C)}\ 1107 \qquad \textbf{(D)}\ 1116 \qquad \textbf{(E)}\ 1125</math>
+[[2024 AMC 8 Problems/Problem 15|Solution]]
+==Problem 16==
+Minh enters the numbers <math>1</math> through <math>81</math> into the cells of a <math>9 \times 9</math> grid in some order. She calculates the product of the numbers in each row and column. What is the least number of rows and columns that could have a product divisible by <math>3</math>?
+<math>\textbf{(A) } 8\qquad\textbf{(B) } 9\qquad\textbf{(C) } 10\qquad\textbf{(D) } 11\qquad\textbf{(E) } 12</math>
+[[2024 AMC 8 Problems/Problem 16|Solution]]
 ==Problem 17==
- Let <math>\text{x=2024}</math>. Compute the last three digits of <math>((x^3-(x-8)^3)^4-(x-69)^2)^5</math>.
+A chess king is said to ''attack'' all squares one step away from it (basically any square right next to it in any direction), horizontally, vertically, or diagonally. For instance, a king on the center square of a 3 x 3 grid attacks all 8 other squares, as shown below. Suppose a white king and a black king are placed on different squares of 3 x 3 grid so that they do not attack each other. In how many ways can this be done?
-NO CALCULATORS ARE ALLOWED.
+<asy>
+/* AMC8 P17 2024, revised by Teacher David */
+unitsize(29pt);
+import math;
+add(grid(3,3));
-Try this.
+pair [] a = {(0.5,0.5), (0.5, 1.5), (0.5, 2.5), (1.5, 2.5), (2.5,2.5), (2.5,1.5), (2.5,0.5), (1.5,0.5)};
+for (int i=0; i<a.length; ++i) {
+    pair x = (1.5,1.5) + 0.4*dir(225-45*i);
+    draw(x -- a[i], arrow=EndArrow());
+}
+label("$K$", (1.5,1.5));
+</asy>
+<math>\textbf{(A)}\ 20 \qquad \textbf{(B)}\ 24 \qquad \textbf{(C)}\ 27 \qquad \textbf{(D)}\ 28 \qquad \textbf{(E)}\ 32</math>
+[[2024 AMC 8 Problems/Problem 17|Solution]]
 ==Problem 18==
-hi guys. trying to cheat? im ashamed of you
+Three concentric circles centered at <math>O</math> have radii of <math>1</math>, <math>2</math>, and <math>3</math>. Points <math>B</math> and <math>C</math> lie on the largest circle. The region between the two smaller circles is shaded, as is the portion of the region between the two larger circles bounded by central angle <math>BOC</math>, as shown in the figure below. Suppose the shaded and unshaded regions are equal in area. What is the measure of <math>\angle{BOC}</math> in degrees?
-code: nsb
+<asy>
+size(100);
+import graph;
+draw(circle((0,0),3));
+real radius = 3;
+real angleStart = -54;  // starting angle of the sector
+real angleEnd = 54;  // ending angle of the sector
+label("$O$",(0,0),W);
+pair O = (0, 0);
+filldraw(arc(O, radius, angleStart, angleEnd)--O--cycle, lightgray);
+filldraw(circle((0,0),2),lightgray);
+filldraw(circle((0,0),1),white);
+draw((1.763,2.427)--(0,0)--(1.763,-2.427));
+label("$B$",(1.763,2.427),NE);
+label("$C$",(1.763,-2.427),SE);
+</asy>
+<math>\textbf{(A)}\ 108 \qquad \textbf{(B)}\ 120 \qquad \textbf{(C)}\ 135 \qquad \textbf{(D)}\ 144 \qquad \textbf{(E)}\ 150</math>
+[[2024 AMC 8 Problems/Problem 18|Solution]]
 ==Problem 19==
-Write your AoPS name here if you took the AMC 8.
+Jordan owns 15 pairs of sneakers. Three fifths of the pairs are red and the rest are white. Two thirds of the pairs are high-top and the rest are low-top. The red high-top sneakers make up a fraction of the collection. What is the least possible value of this fraction?
+[[File:2024-amc-8-q19.png|center|500px|caption]]
-Probablity
+<math>\textbf{(A) } 0\qquad\textbf{(B) } \dfrac{1}{5} \qquad\textbf{(C) } \dfrac{4}{15} \qquad\textbf{(D) } \dfrac{1}{3} \qquad\textbf{(E) } \dfrac{2}{5}</math>
-NapoleonicAviator
-Multpi12
+[[2024 AMC 8 Problems/Problem 19|Solution]]
-funbeast
-mathkindacool_
-Rainier2020
 ==Problem 20==
-Find the sum of the square root of -2 and the last digit of pi.
+Any three vertices of the cube <math>PQRSTUVW,</math> shown in the figure below, can be connected to form a triangle. <math>(</math>For example, vertices <math>P, Q,</math> and <math>R</math> can be connected to form <math>\triangle{PQR}.)</math> How many of these triangles are equilateral and contain <math>P</math> as a vertex?
-<math>(A) 2+\sqrt2i (B)3+\sqrt2i (C) 4+\sqrt2i (D) 5+\sqrt2i (E) 7+\sqrt2i</math>
+<asy>
+unitsize(4);
+pair P,Q,R,S,T,U,V,W;
+P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);
+draw(W--V); draw(V--Q); draw(Q--P); draw(P--W); draw(T--U); draw(U--R); draw(R--S); draw(S--T); draw(W--T); draw(P--S); draw(V--U); draw(Q--R);
+dot(P);
+dot(Q);
+dot(R);
+dot(S);
+dot(T);
+dot(U);
+dot(V);
+dot(W);
+label("$P$",P,NW);
+label("$Q$",Q,NW);
+label("$R$",R,NE);
+label("$S$",S,N);
+label("$T$",T,NE);
+label("$U$",U,NE);
+label("$V$",V,SE);
+label("$W$",W,SW);
+</asy>
+<math>\textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }2\qquad\textbf{(D) }3\qquad\textbf{(E) }6</math>
+[[2024 AMC 8 Problems/Problem 20|Solution]]
 ==Problem 21==
-what is 9+10?
+A group of frogs (called an ''army'') is living in a tree. A frog turns green when in the shade and turns yellow
+when in the sun. Initially, the ratio of green to yellow frogs was <math>3 : 1</math>. Then <math>3</math> green frogs moved to the
+sunny side and <math>5</math> yellow frogs moved to the shady side. Now the ratio is <math>4 : 1</math>. What is the difference
+between the number of green frogs and the number of yellow frogs now?
-(A) 21 (B) 69 (C) 19 (D) nothing (E) something
+<math>\textbf{(A) } 10\qquad\textbf{(B) } 12\qquad\textbf{(C) } 16\qquad\textbf{(D) } 20\qquad\textbf{(E) } 24</math>
+[[2024 AMC 8 Problems/Problem 21|Solution]]
 ==Problem 22==
-What is the sum of the cubes of the solutions cubed of <math>x^5+2x^4+3x^3+3x^2+2x+1=0</math>?
+A  roll of tape is <math>4</math> inches in diameter and is wrapped around a ring that is <math>2</math> inches in diameter. A cross section of the tape is shown in the figure below. The tape is <math>0.015</math> inches thick. If the tape is completely unrolled, approximately how long would it be? Round your answer to the nearest <math>100</math> inches.
+<asy>
+/* AMC8 P22 2024, revised by Teacher David */
+size(150);
+pair o = (0,0);
+real r1 = 1;
+real r2 = 2;
+filldraw(circle(o, r2), mediumgray, linewidth(1pt));
+filldraw(circle(o, r1), white, linewidth(1pt));
+draw((-2,-2.6)--(-2,-2.4));
+draw((2,-2.6)--(2,-2.4));
+draw((-2,-2.5)--(2,-2.5), L=Label("4 in."));
+draw((-1,0)--(1,0), L=Label("2 in.", align=(0,1)), arrow=Arrows());
-(A) 1 (B) 8 (C) 27 (D) -1 (E) -27
+draw((2,0)--(2,-1.3), linewidth(1pt));
+</asy>
+<math>\textbf{(A) } 300\qquad\textbf{(B) } 600\qquad\textbf{(C) } 1200\qquad\textbf{(D) } 1500\qquad\textbf{(E) } 1800</math>
 [[2024 AMC 8 Problems/Problem 22|Solution]]
@@ Line 69: / Line 426: @@
 ==Problem 23==
-lol we are the defenders against the cheaters... get outta here and study
+Rodrigo has a very large sheet of graph paper. First he draws a line segment connecting point <math>(0,4)</math> to point <math>(2,0)</math> and colors the <math>4</math> cells whose interiors intersect the segment, as shown below. Next Rodrigo draws a line segment connecting point <math>(2000,3000)</math> to point <math>(5000,8000)</math>. How many cells will he color this time?
+<asy>
+filldraw((0,4)--(1,4)--(1,3)--(0,3)--cycle, gray(.75), gray(.5)+linewidth(1));
+filldraw((0,3)--(1,3)--(1,2)--(0,2)--cycle, gray(.75), gray(.5)+linewidth(1));
+filldraw((1,2)--(2,2)--(2,1)--(1,1)--cycle, gray(.75), gray(.5)+linewidth(1));
+filldraw((1,1)--(2,1)--(2,0)--(1,0)--cycle, gray(.75), gray(.5)+linewidth(1));
+draw((-1,5)--(-1,-1),gray(.9));
+draw((0,5)--(0,-1),gray(.9));
+draw((1,5)--(1,-1),gray(.9));
+draw((2,5)--(2,-1),gray(.9));
+draw((3,5)--(3,-1),gray(.9));
+draw((4,5)--(4,-1),gray(.9));
+draw((5,5)--(5,-1),gray(.9));
+draw((-1,5)--(5, 5),gray(.9));
+draw((-1,4)--(5,4),gray(.9));
+draw((-1,3)--(5,3),gray(.9));
+draw((-1,2)--(5,2),gray(.9));
+draw((-1,1)--(5,1),gray(.9));
+draw((-1,0)--(5,0),gray(.9));
+draw((-1,-1)--(5,-1),gray(.9));
+dot((0,4));
+label("$(0,4)$",(0,4),NW);
+dot((2,0));
+label("$(2,0)$",(2,0),SE);
+draw((0,4)--(2,0));
+draw((-1,0) -- (5,0), arrow=Arrow);
+draw((0,-1) -- (0,5), arrow=Arrow);
+</asy>
+<math>\textbf{(A) }6000\qquad\textbf{(B) }6500\qquad\textbf{(C) }7000\qquad\textbf{(D) }7500\qquad\textbf{(E) }8000</math>
-SubText: and im here writing soulutions for these joke problems. (Multpi12)
+[[2024 AMC 8 Problems/Problem 23|Solution]]
- And so am I ;)
 ==Problem 24==
-wait when are the questions coming tho
-I think it's 1/25 for official answers since all tests end at 1/24
+Jean has made a piece of stained glass art in the shape of two mountains, as shown in the figure below. One mountain peak is <math>8</math> feet high while the other peak is <math>12</math> feet high. Each peak forms a <math>90^\circ</math> angle, and the straight sides form a <math>45^\circ</math> angle with the ground. The artwork has an area of <math>183</math> square feet. The sides of the mountain meet at an intersection point near the center of the artwork, <math>h</math> feet above the ground. What is the value of <math>h?</math>
+<asy>
+unitsize(.3cm);
+filldraw((0,0)--(8,8)--(11,5)--(18,12)--(30,0)--cycle,gray(0.7),linewidth(1));
+draw((-1,0)--(-1,8),linewidth(.75));
+draw((-1.4,0)--(-.6,0),linewidth(.75));
+draw((-1.4,8)--(-.6,8),linewidth(.75));
+label("$8$",(-1,4),W);
+label("$12$",(31,6),E);
+draw((-1,8)--(8,8),dashed);
+draw((31,0)--(31,12),linewidth(.75));
+draw((30.6,0)--(31.4,0),linewidth(.75));
+draw((30.6,12)--(31.4,12),linewidth(.75));
+draw((31,12)--(18,12),dashed);
+label("$45^{\circ}$",(.75,0),NE,fontsize(10pt));
+label("$45^{\circ}$",(29.25,0),NW,fontsize(10pt));
+draw((8,8)--(7.5,7.5)--(8,7)--(8.5,7.5)--cycle);
+draw((18,12)--(17.5,11.5)--(18,11)--(18.5,11.5)--cycle);
+draw((11,5)--(11,0),dashed);
+label("$h$",(11,2.5),E);
+</asy>
+<math>\textbf{(A)}\ 4 \qquad \textbf{(B)}\ 5 \qquad \textbf{(C)}\ 4\sqrt{2} \qquad \textbf{(D)}\ 6 \qquad \textbf{(E)}\ 5\sqrt{2}</math>
+[[2024 AMC 8 Problems/Problem 24|Solution]]
 ==Problem 25==
-If Bob is travelling at the speed of 3 George Washington, how long will it take for him to finish his chutney.
+A small airplane has <math>4</math> rows of seats with <math>3</math> seats in each row. Eight passengers have boarded the plane and are distributed randomly among the seats. A married couple is next to board. What is the probability there will be <math>2</math> adjacent seats in the same row for the couple?
+[[Image:2024_AMC_8-Problem_25.png|center|150px]]
+<math>\textbf{(A)}\ \dfrac{8}{15} \qquad \textbf{(B)}\ \dfrac{32}{55} \qquad \textbf{(C)}\ \dfrac{20}{33} \qquad \textbf{(D)}\ \dfrac{34}{55} \qquad \textbf{(E)}\ \dfrac{8}{11}</math>
-A) 13 Hours
+[[2024 AMC 8 Problems/Problem 25|Solution]]
-B) 7 minute
-C) NA
-D) 12 Neptunes
-E) IDK
 ==See Also==
-{{AMC8 box|year=2024|before=[[2023 AMC 8 Problems|2023 AMC 8]]|after=[[2100 AMC 8 Problems|2025 AMC 8]]}}
+{{AMC8 box|year=2024|before=[[2023 AMC 8 Problems|2023 AMC 8]]|after=[[2025 AMC 8 Problems|2025 AMC 8]]}}
 * [[AMC 8]]
 * [[AMC 8 Problems and Solutions]]
 * [[Mathematics competition resources|Mathematics Competition Resources]]