Difference between revisions of "2008 AMC 10B Problems/Problem 17"
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==Solution== | ==Solution== | ||
− | { | + | The pollster could select responses in 3 different ways: YNN, NYN, and NNY, where Y stands for a voter who approved of the work, and N stands for a person who didnt approve of the work. The probability of each of these is <math>(0.7)(0.3)^2=0.063.</math> Thus, the answer is <math>3 \cdot 0.063=0.189\Rightarrow \boxed{B}</math> |
==See also== | ==See also== | ||
{{AMC10 box|year=2008|ab=B|num-b=16|num-a=18}} | {{AMC10 box|year=2008|ab=B|num-b=16|num-a=18}} |
Revision as of 10:59, 27 August 2008
Problem
A poll shows that of all voters approve of the mayor's work. On three separate occasions a pollster selects a voter at random. What is the probability that on exactly one of these three occasions the voter approves of the mayor's work?
Solution
The pollster could select responses in 3 different ways: YNN, NYN, and NNY, where Y stands for a voter who approved of the work, and N stands for a person who didnt approve of the work. The probability of each of these is Thus, the answer is
See also
2008 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |